Answer:
20.446cm3
Explanation:
The following were obtained from the question given:
V1 (initial volume) = 24.568 cm3
T1 (initial temperature) = 25°C = 25 + 273 = 298K
T2 (final temperature) = - 25°C = - 25 + 273 = 248K
V2 (final volume) = ?
Since the pressure is constant, the gas is obeying Charles' law. With the Charles' law equation V1/T1 = V2/T2, we can easily calculate the final volume as follow:
V1/T1 = V2/T2
24.568/298 = V2/248
Cross multiply to express in linear form as shown below:
298 x V2 = 24.568 x 248
Divide both side by 298
V2 = (24.568 x 248) /298
V2 = 20.446cm3
From the calculations made above, the volume of the gas at -25°C is 20.446cm3
0.73 M is the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sample of the sulfuric acid solution.
Explanation:
Data given:
Volume of the base = 47 ml
molarity of the base= 0.39 M
volume of the acid = 25 ml
molarity of the acid =?
For titration reaction between acid and base, the volume or molarity of any of the base or acid can be determined. The formula used:
Macid X Vacid = Vbase x Mbase
Macid = 
putting the values given in the rearranged equation above:
Macid = 
= 0.73 M
The concentration of the sulphuric acid needed is 0.73 M.
The reaction, 2 C4H10 (g) + 13 O2 (g) = 8 CO2 (g) + 5 H2O (g), is the combustion of butane. A combustion reaction involves the reaction of a hydrocarbon with oxygen producing carbon dioxide and water. This reaction is exothermic which means it releases energy in the form of heat. Therefore, as the reaction proceeds,a heat energy is being given off by the reaction. This happens because the total kinetic energy of the reactants is greater than the total kinetic energy of the products. So, the excess energy should be given off somewhere which in this case is released as heat.
Answer:
Los parámetros dados del movimiento son;
La velocidad con la que el atleta se dirige hacia la línea de salida = 6 m / s
El punto en el que se inicia el cronómetro = marca de 100 m
La ecuación para la distancia recorrida, 's', se da como sigue;
s = 6 m / s × t
La distancia total recorrida, d = 100 + s
∴ d = 100 + 6·t
Los gráficos de las ecuaciones se crean con Microsoft Excel y se presentan de la siguiente manera;
Explanation: