All categories

3 years ago

Why objects float in outer space?

Chemistry

2 answers:

viktelen [127]3 years ago

7 0

Because there is no gravity

Bingel [31]3 years ago

3 0

Answer:

There is no gravity. No force pulls the object down so it cant fall.

Explanation:

You might be interested in

Consider the above reaction using 25.0 mL of tert-butyl alcohol (d = 0.786 g/mL) with 60.0 mL of concentrated hydrobromic acid (

Liono4ka [1.6K]

Answer:

Theoretical yield: 36,3g

Percent yield: 71,9%

Explanation:

The reaction of tert-butyl alcohol with hydrobromic acid to produce tert-butyl bromide is a 1:1 reaction.

Moles of tert-butyl alcohol in 25,0 mL are:

25,0mL × (0,786g / mL) × (1mol / 74,12g) = 0,265 moles of tert-butyl alcohol

Moles of hydrobromic acid are:

60,0mL× 47,0% × (1,49g / mL) × (1mol / 80,91g) = 0,519 moles of HBr

As moles of tert-butyl alcohol are less than moles of HBr, limiting reactant is tert-butyl alcohol.

Theoretical yield of tert-butyl bromide in grams is:

0,265 moles × (137,02g / 1mol) = 36,3g

Percent yield:

26,1g / 36,3g × 100 = 71,9%

The reactions are in the image.

There are many ways to produce alkyl halides from primary and secondary alcohols. The reaction in this case is the Appel reaction.

The reaction of tertiary alkyl halides may undergo a hydrolysis reaction -under proper conditions- to form an alcohol and a hydrogen halide.

I hope it helps!

5 0

4 years ago

When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H

Taya2010 [7]

Answer:

- Empirical:

$C_3H_7$

- Molecular:

$C_6H_{14}$

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

$n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC$

Moreover, the moles of hydrogen:

$n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH$

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

$C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}$

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

$C_3H_7$

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

$C_6H_{14}$

Which is hexane.

Best regards.

6 0

4 years ago

Calculate the pH during the titration of 20.00 mL of 0.1000 M HNO2(aq) with 0.1000 M KOH(aq) after 13.27 mL of the base have bee

Slav-nsk [51]

Answer:

pH = 2.462.

Explanation:

Hello there!

In this case, according to the reaction between nitrous acid and potassium hydroxide:

$HNO_2+KOH\rightarrow KNO_2+H_2O$

It is possible to compute the moles of each reactant given their concentrations and volumes:

$n_{HNO_2}=0.02000L*0.1000mol/L=2.000x10^{-3}mol\\\\n_{KOH}=0.1000mol/L*0.01327L=1.327x10^{-3}mol$

Thus, the resulting moles of nitrous acid after the reaction are:

$n_{HNO_2}=2.000x10^{-3}mol-1.327x10^{-3}mol=6.73x10^{-4}mol$

So the resulting concentration considering the final volume (20.00mL+13.27mL) is:

$[HNO_2]=\frac{6.73x10^{-4}mol}{0.01327L+0.02000L} =0.02023M$

In such a way, we can write the ionization of this weak acid to obtain:

$HNO_2+H_2O\rightleftharpoons NO_2^-+H_3O^+$

So we can set up its equilibrium expression to obtain x as the concentration of H3O+:

$Ka=\frac{[NO_2^-][H_3O^+]}{[HNO_2]}\\\\7.1x10^{-4}=\frac{x^2}{0.02023M-x}$

Next, by solving for the two roots of x, we get:

$x_1=-0.004161M\\\\x_2=0.003451M$

Whereas the correct value is 0.003451 M. Finally, we compute the resulting pH:

$pH=-log(0.003451)\\\\pH=2.462$

Best regards!

4 0

3 years ago

You can use __________ to check that answer is reasonable.

Maru [420]

A calculator .... that's the answer

4 0

4 years ago

The pH of a solution prepared by the addition of 100mL 0.002M HCL to 100mL distilled water is closest to:

IRISSAK [1]

Answer:

d.3.0

Explanation:

Step 1: Calculate the final volume of the solution

The final volume is equal to the sum of the volumes of the initial HCl solution and the volume of distilled water.

V₂ = 100 mL + 100 mL = 200 mL

Step 2: Calculate the final concentration of HCl

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂ = 0.002 M × 100 mL/200 mL = 0.001 M

Step 3: Calculate the pH of the final HCl solution

Since HCl is a strong acid, [H⁺] = HCl. We will use the definition of pH.

pH = -log [H⁺] = -log 0.001 = 3

7 0

3 years ago