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kotegsom [21]
4 years ago
12

I don't know the answer

Physics
1 answer:
tia_tia [17]4 years ago
4 0
So add both the 15meters and 13centimeters together
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An atom with five protons six neutrons and five electrons has an atomic mass of
Ainat [17]

The atomic mass of this question is 10.811

4 0
4 years ago
300kg of water are lifted 10m vertically in 5s show the work done in 30kj and that power is 6kw . Please help me​
Mandarinka [93]

Answer:

6KW

Explanation:

The computation is shown below:

We know that

Work done= m ×g× h

Here

W= 300×10×10

= 30000 J

= 30 KJ

And

Power= Work done ÷time taken

 P = 30000 ÷ 5

= 6000W

= 6KW

The above represent the answer

3 0
3 years ago
A student plucks a fixed-end string, creating a standing wave with 6.00 nodes (including any nodes at the ends). The string is t
Vesna [10]

1) 2.5 wavelengths

2) 0.208 m

3) 1731 Hz

Explanation:

1)

Standing waves are waves that do not propagate, but instead the particles of the medium just oscillate around a fixed position. Examples of standing waves are the waves produced on a string with fixed ends.

The points of a standing wave in which the amplitude of the oscillation is always zero are called nodes.

The two fixed ends of the string are two nodes. In this problem, we have a total of 6 nodes along the string: this means that there are 4 additional nodes apart from the two ends of the string.

Therefore, this also means that the string oscillate in 5 different segments.

One wavelength is equal to 2 segments of the oscillation: therefore, since here there are 5 segments, this means that the number of wavelengths that we have in this string is

n=\frac{5}{2}=2.5

2)

The wavelength of a wave is the distance between two consecutive crests (or throughs) of the wave.

The wavelength of a standing wave can be also measured as the distance between the nth-node and the (n+2)-th node: so, basically, the wavelength in a standing wave is twice the distance between two nodes:

\lambda = 2 d

where

\lambda is the wavelength

d is the distance between two nodes

Here the length of the string is

L = 0.520 m

And since it oscillates in 5 segments, the  distance between two nodes is

d=\frac{L}{5}=\frac{0.520}{5}=0.104 m

And therefore, the wavelength is

\lambda=2d=2(0.104)=0.208 m

3)

The frequency of a wave is the number of complete oscillations of the wave per second.

The frequency of a wave is related to its speed and wavelength by the wave equation:

v=f\lambda

where

v is the speed

f is the frequency

\lambda is the wavelength

In this problem:

v = 360 m/s is the speed of the wave

\lambda=0.208 m is the wavelength

Therefore, the frequency is

f=\frac{v}{\lambda}=\frac{360}{0.208}=1731 Hz

3 0
3 years ago
Anne has a sample of a substance. Its volume is 20 cm3, and its mass is 100 grams. What is the sample’s density?
JulsSmile [24]
The answer is:  " 5 g / cm³ " .
____________________________________________
Explanation:  
____________________________________________
Density = mass divided by volume ; or: "D = m / V " ;
____________________________________________
    and is expressed as:  "mass per unit volume" ;

The mass, "m", is expressed in units of "g" (grams) ; and
the volume, "V" is expressed in units of "cm³ " or "mL" ; ("cm³ ", in this case);

{Note the exact conversion:  " 1 cm³ = 1 mL " .} .
_____________________________________________________
So, if:  the mass, "m = 100 g"  {given} ; 

and the volume,  " V = 20 cm³ " {given} ;
_______________________________
Plug these values into the formula/equation to solve for the density, "D" ;
________________________________________________
    D =  m / V =  (100 g) / (20 cm³)  
 
         = (100 ÷ 20)  g / cm³  = 5 g /cm³ .
____________________________________________
    The answer is:  " 5 g / cm³ " .
______________________________________________________
8 0
3 years ago
How much kinetic energy would a 65 kg person required to escape from the earth's gravitational field
stellarik [79]

The kinetic energy needed by the man is 4.5\cdot 10^9 J

Explanation:

The escape velocity (the speed needed by an object in the Earth's surface to escape the Earth's gravitational field) is given by

v=\sqrt{\frac{2GM}{R}}

where

G is the gravitational constant

M is the Earth's mass

R is the radius of the Earth

For the Earth, we have

M=5.97\cdot 10^{24} kg

R=6.37\cdot 10^6 m

Substituting, we find the escape velocity:

v=\sqrt{\frac{2(6.67\cdot 10^{-11})(5.97\cdot 10^{24})}{6.37\cdot 10^6}}=1.18\cdot 10^4 m/s

Now we can find the kinetic energy that the man would need, which is given by

K=\frac{1}{2}mv^2

where

m = 65 kg is the mass of the person

v=1.18\cdot 10^4 m/s is the escape velocity

Substituting,

K=\frac{1}{2}(65)(1.18\cdot 10^4)^2=4.5\cdot 10^9 J

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

3 0
3 years ago
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