Question

How much kinetic energy would a 65 kg person required to escape from the earth's gravitational field

Answer 1

The kinetic energy needed by the man is $4.5\cdot 10^9 J$

Explanation:

The escape velocity (the speed needed by an object in the Earth's surface to escape the Earth's gravitational field) is given by

$v=\sqrt{\frac{2GM}{R}}$

where

G is the gravitational constant

M is the Earth's mass

R is the radius of the Earth

For the Earth, we have

$M=5.97\cdot 10^{24} kg$

$R=6.37\cdot 10^6 m$

Substituting, we find the escape velocity:

$v=\sqrt{\frac{2(6.67\cdot 10^{-11})(5.97\cdot 10^{24})}{6.37\cdot 10^6}}=1.18\cdot 10^4 m/s$

Now we can find the kinetic energy that the man would need, which is given by

$K=\frac{1}{2}mv^2$

where

m = 65 kg is the mass of the person

$v=1.18\cdot 10^4 m/s$ is the escape velocity

Substituting,

$K=\frac{1}{2}(65)(1.18\cdot 10^4)^2=4.5\cdot 10^9 J$

Learn more about kinetic energy:

brainly.com/question/6536722

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