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castortr0y [4]
3 years ago
11

Anne has a sample of a substance. Its volume is 20 cm3, and its mass is 100 grams. What is the sample’s density?

Physics
1 answer:
JulsSmile [24]3 years ago
8 0
The answer is:  " 5 g / cm³ " .
____________________________________________
Explanation:  
____________________________________________
Density = mass divided by volume ; or: "D = m / V " ;
____________________________________________
    and is expressed as:  "mass per unit volume" ;

The mass, "m", is expressed in units of "g" (grams) ; and
the volume, "V" is expressed in units of "cm³ " or "mL" ; ("cm³ ", in this case);

{Note the exact conversion:  " 1 cm³ = 1 mL " .} .
_____________________________________________________
So, if:  the mass, "m = 100 g"  {given} ; 

and the volume,  " V = 20 cm³ " {given} ;
_______________________________
Plug these values into the formula/equation to solve for the density, "D" ;
________________________________________________
    D =  m / V =  (100 g) / (20 cm³)  
 
         = (100 ÷ 20)  g / cm³  = 5 g /cm³ .
____________________________________________
    The answer is:  " 5 g / cm³ " .
______________________________________________________
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5 0
4 years ago
A 1.7-kg firework is fired from the ground straight up on a planet with whose acceleration due to gravity is 4.8 m/s/s. You want
Sunny_sXe [5.5K]

Answer:

41.0 m/s, 10.6 s

Explanation:

Given:

a = -4.8 m/s²

Δy = 165 m

v = -10.0 m/s

Find: v₀ and t

v² = v₀² + 2aΔy

(-10.0 m/s)² = v₀² + 2(-4.8 m/s²) (165 m)

v₀ = 41.0 m/s

Δy = vt − ½ at²

165 m = (-10.0 m/s) t − ½ (-4.8 m/s²) t²

165 = -10t + 2.4t²

0 = 2.4t² − 10t − 165

Solve with quadratic formula:

t = [ -(-10) ± √((-10)² − 4(2.4)(-165)) ] / 2(2.4)

t = (10 ± √1684) / 4.8

t = 10.6 s

4 0
3 years ago
A rock is thrown vertically upward with a speed of 18.0 m/s from the roof of a building that is 50.0 m above the ground. Assume
Andreyy89

Answer:

(a) 5.7 s

(b) 39 m/s

Explanation:

(a) u = 18 m/s

At the maximum height, the final velocity of ball is zero. lte teh time taken by the ball to go from 50 m height to maximum height is t.

use first equation of motion.

v = u + g t

0 = 18 - 10 x t

t = 1.8 s

Let the maximum height attained by the ball when it thrown from 50 m height is h'.

Use third equation of motion

v^2 = u^2 + 2 g h'

0 = 18^2 - 2 x 10 x h'

h' = 16.2 m

Total height from the ground H = h + h' = 50 + 16.2 = 76.2 m

Let t' be the time taken by the ball to hit the ground as it falls from maximum height.

use third equation of motion

H = ut + 1/2 x g t'^2

76.2 = 0 + 1/2 x 10 x t'^2

t' = 3.9 s

Total time taken by the ball to hit the ground = T = t + t' = 1.8 + 3.9 = 5.7 s

(b) Let v be the velocity with which the ball strikes the ground.

v^2 = u^2 + 2 g H

v^2 = 0 + 2 x 10 x 76.2

v = 39 m/s

4 0
4 years ago
A hill that has a 36.1% grade is one that rises 36.1 m vertically for every 100.0 ml of distance in the horizontal direction. At
GaryK [48]

Answer:

angle is 19.85°

Explanation:

given data

grade = 36.1 %

vertically distance y = 36.1 m

horizontal distance x = 100 m

to find out

angle

solution

we know that according to question here

it make a triangle shape that contain 100 m base and height 36.1 m

and make angle with base is θ

so by triangle we know here

tanθ = y/x   ..........1

so we now put x and y and find θ

tanθ = 36.1 / 100

tanθ = 0.361

θ = 19.85°

so angle is 19.85°

7 0
3 years ago
Give an example for each of the following, where the force:
max2010maxim [7]

Explanation:

  • A cricket player hitting the ball from opposite direction.
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  • Heating of a plastic bottle.
  • Applying brake of a car.
  • rolling a stopped marble on a table.

7 0
3 years ago
Read 2 more answers
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