For Fraunhofer diffraction at a single slit would be represented by:
<span>a sinθ = mλ
</span><span>It should be noted that the angle needs be halved because we are only concerned with the angle between m=1 and m=0 and they gave you the angle between m=1 to the right of the center and m=1 on the left of the center. We calculate as follows:
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<span>a sin(45/2)=(1)(470)
a = 1228 nm
Hope this answers the question. Have a nice day.
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This has a two word answer: sun's heat. The faster moving molecules near the ocean's surface are provided with enough energy from the sun to escape the surface they are near.
Answer:
10.89 J.
Explanation:
The following data were obtained from the question:
Mass (m) = 12.5 kg
Velocity (v) = 1.32 m/s
Work done =?
To obtain the workdone, we shall determine the kinetic energy of the object since work and energy has the same unit of measurement. This is illustrated below:
Mass (m) = 12.5 kg
Velocity (v) = 1.32 m/s
Kinetic energy (K.E) =?
K.E = ½mv²
K.E = ½ × 12.5 × 1.32²
K.E = 6.25 × 1.7424
K.E = 10.89 J
The kinetic energy of the object is 10.89 J. Hence, the workdone in bringing the object to rest is 10.89 J.
<span>The Special (as in Limited) Theory of Relativity, is a simplification of the General Theory of Relativity.
Essentially, if you eliminate acceleration, and any significant mass from the General Theory, you get the Special Theory.
Evidence for Special Relativity (solar moons for example), is also evidence for the General Theory. The General Theory is supported by:
- Universal expansion
- the spin down of binary pulsars
- frame dragging
- gravitational lensing
- gravitational time dilation</span><span>
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