Question

Three dogs are fighting over a bone. One is pulling to the left with a force of 20N, another

Answer 1

Answer:

Net force = 21.12 N

angle for the force α = 45°

Explanation:

In this problem, we will take the left as the negative x-axis, the right as the positive x-axis, and the upward direction as the positive y-axis.

The 20 N force to the left has an x component of -20 N, and y component of 0 N

The 35 N force to the right has a x component of 35 N, and a y component of 0 N

The 15 N upwards has an x component of 0 N, and a y component of 15 N

We resolve the forces into the x and y components.

for the x component Fx

Fx = -20 + 35 + 0 = 15 N

For the y component Fy

Fy = 0 + 0 + 15 = 15 N

Net force Fn = $\sqrt{Fx^{2} + Fy^{2} }$

$Fn = \sqrt{(15)^{2} + (15^{2} ) }$

Net force Fn = 21.21 N

for the angle,

$tan\alpha = \frac{Fy}{Fx} = \frac{15}{15}$

$tan\alpha = 1$

α = $tan^{-1}$ 1

angle for force α = 45°