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ANEK [815]
3 years ago
15

____________ is considered one of the great geniuses and gave us the formula, E=mc2.

Physics
2 answers:
r-ruslan [8.4K]3 years ago
7 0
Albert Einstein is your answer.
GarryVolchara [31]3 years ago
3 0

Answer:

Albert Einstein

Explanation:

In 1905, Albert Einstein wrote a scientific article called "Does the Inertia of a Body Depend Upon Its Energy Content?" in which he established that energy (E) can turn into matter (m) and vice versa. This conversion is given by a constant, which is the speed of light squared (c^2).

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Tartaric acid is present in spinach true or false ​
sertanlavr [38]

Answer:

<h2>false</h2>

Explanation:

because Oxalic acid is present in spinach

<h2>MARK ME AS BRAINLIST</h2>
7 0
3 years ago
Your brother bikes 350 miles in 27 seconds how fast did he go
Harrizon [31]
His speed is exactly (350/27) miles per second ... about 46,667 mph. Wotta guy !
6 0
3 years ago
There are about 11,200,000 billion metric tons of in the atmosphere. Based on an estimated photosynthesis rate of 600 billion me
zhannawk [14.2K]

Answer:

-48,800,000 or 71,200,000

Explanation:

subtraction or addition :D

I hope I helpped (ㆁωㆁ)

3 0
3 years ago
Two charged particles, q1 and q2, are located on the x-axis, with q1 at the origin and q2 initially atx1 = 14.7 mm.In this confi
Sladkaya [172]

Answer:

The force magnitude is 1.75 μN acting outward from the origin towards x₂

Explanation:

The given parameters, are;

The location of q₁ = The origin

The location of q₂ = 14.7 mm from q₁

The repulsive force exerted on q₂ by q₁ = 2.62 μN

The location the particle q₂ is located to =  18.0 mm from q₁

By Coulomb's law, we have;

F = k\dfrac{q_1 \times q_2 }{r^2}

Where;

k = Coulomb constant ≈ 8.99 × 10⁹ kg·m³/(s²·C²)

r = The distance between the particles

F = The force acting between the particles

When r = 14.7 mm F = 2.62 μN

∴ q₂ × q₁ = r² × F/k = (14.7×10^(-3))²×2.62×10^(-6)/(8.9875517923^9) ≈ 1.48 × 10⁻¹⁸

q₂ × q₁ = 1.48 × 10⁻¹⁸ C²

When the distance is increased to 18.0 mm, we have;

F = (8.9875517923^9) × 1.4796647 × 10^(-18)/((18×10^(-3))²) = 1.75 × 10⁻⁶ N

∴ F = 1.75 μN.

Therefore;

The force magnitude is 1.75 μN outward from the origin towards  x₂.

8 0
3 years ago
A rock on the ground weighs 40N. How much force does the ground exert on the rock?
worty [1.4K]

Answer:

The correct option is;

C. 40 N

Explanation:

Given that the rock is on the ground, we have;

The weight of the rock, F_W = 40 N ↓

From Newton's third law of motion, we have that action and reaction are equal and opposite,

Therefore, given that the weight of the rock exerts a force of 40 N on the ground, and the rock is stable and stationery on the ground, then the ground is reacting to the weight of the rock with an equal force of 40 N, acting in opposite direction to the weight of the block to balance the weight of the rock and create equilibrium such that the net force acting on the rock is zero

∑F = F_W + F_R = 0

Where;

F_R = The reaction of the ground

We have;

F_W + F_R= 40 + F_R  = 0

F_R = 0 - 40 = -40

F_R = -40 N ↓

∴ F_R = 40 N ↑.

5 0
3 years ago
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