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Andrews [41]
3 years ago
10

Can i get help with this?

Mathematics
2 answers:
diamong [38]3 years ago
5 0

The answer is -6 and 8

nekit [7.7K]3 years ago
4 0

one point should go on 8 and another on -6

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Compute 1 + 2 + 3 +....+ 1,997 + 1,998 + 1,999
sp2606 [1]

Answer:

1 999 000

Step-by-step explanation:

Formula:

1+2+3+.\ .\ .+n=\frac{n\times \left( n+1\right)  }{2}

………………………………………

Then

1+2+3+....+1997+1998+1999=\frac{1999\times \left( 1999+1\right)  }{2}

1+2+3+....+1997+1998+1999=\frac{1999\times \left( 2000\right)  }{2}

1+2+3+....+1997+1998+1999=\frac{3998000  }{2}

1+2+3+....+1997+1998+1999=1999000

7 0
2 years ago
Write the first five terms of the arithmetic sequence. a4 = 22, a10 = 64
dedylja [7]
Hello :
the general term is : 
an = a1+(n-1)×d  
or : an = ap +(n-p)×d......d is common diffrence
let : n=10 and p= 4
a10 =  a4 +(10-4)×d
64 = 22 + 6d
6d =  42
d= 7
conclusion :
a4 = 22
a3 = 22-7=15
a2=15-7=8
a1= 8-7=1
<span>the first five terms : 1 , 8 , 15 , 22</span>

4 0
3 years ago
Lots of points plzzz help. What are m
lara31 [8.8K]

Answer:

???

Step-by-step explanation:

6 0
2 years ago
The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p
VLD [36.1K]

Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

\chi^2_{1-\frac{\alpha}{2}}= 51.770

Chi square critical value for upper tail =

\chi^2_{\frac{\alpha}{2}}= 81.085

80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0
3 years ago
A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
kkurt [141]

Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

2b^2+4bh=36

b^2+2bh=18

2bh=18-b^2

h=\frac{18-b^2}{2b}

Volume of box, V=b^2h

Substitute the values

V=b^2\times \frac{18-b^2}{2b}

V=\frac{1}{2}(18b-b^3)

Differentiate w. r.t b

\frac{dV}{db}=\frac{1}{2}(18-3b^2)

\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

\implies 3b^2=18

b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}

h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

7 0
3 years ago
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