We can re arrange this:
(-5)*(4) * x^6 * x * x^8 * y * y^6 * z^9 * z^9
using exponent properties
we can get
-20 x^15 y^7 z^18
as our simplified answer.
Since the 6 is in the hundreds place and it is above 5, then you round the thousands place up one to 88000
It is <span>Round 0.172 to the nearest hundredth.</span>
Answer: if Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.
Explanation:
Given that a triangle ABC is reflected in triangle A'B'C'
Here reflection is done on a line
If you imagine the line as a mirror then ABC will have image on the mirror line as A'B'C'
Recall that in a mirror the object and image would be equidistant from the mirror and also the line joining the image and object would be perpendicular to the mirror
But note that corresponding images will only be perpendicular bisector to the line
So A and A' only will be corresponding so AA' will have mid point on line
Option 1 is right
