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ASHA 777 [7]
3 years ago
10

What is an atom? Give three 3 examples.​

Physics
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

<u>Atom</u><u> </u><u>is </u><u>particle</u><u> </u><u>of </u><u>matter</u><u> </u><u>that </u><u>uniquely</u><u> </u><u>defines</u><u> </u><u>a</u><u> </u><u>chemical</u><u> </u><u>element</u><u>.</u>

Examples of atom:

  • Hydrogen [ H]
  • Neon [Ne]
  • Argon [A]
  • Iron [Fe]
  • Calcium [Ca]

<h3>About Atom:</h3>

Atom consists of a central nucleus that is usually surrounded by one or more electrons .Each electron is negatively charged. The nucleus is positively charged and contains one or more relatively heavy particles known as protons and neutrons.

An early model of the atom was developed by the physicist Ernest Rutherford in 1913. He was the first to suggest that atoms are like miniature solar systems except that the attractive force is not caused by gravity, but by opposing electrical charged.

Hope this helps....

Good luck on your assignment...

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aksik [14]

Answer:

-12.12

Explanation:

i just added them together and it worked.

4 0
2 years ago
The distance between the centers of the wheels of a motorcycle is 156 cm. The center of mass of the motorcycle, including the ri
Drupady [299]

Answer:

a = 9.86 m/s²

Explanation:

given,

distance between the centers of wheel = 156 cm

center of mass of motorcycle including rider = 77.5 cm

horizontal acceleration of motor cycle = ?

now,

The moment created by the wheels must equal the moment created by gravity.

take moment about wheel as it touches the ground, here we will take horizontal distance between them.

then, take the moment around the center of mass. Since the force on the ground from the wheels is horizontal, we need the vertical distance.

now equating both the moment

m g d = F h

d is the horizontal distance

h is the vertical distance

m g d = m a h

term of mass get eliminated

g d = a h

so,

a = \dfrac{g\ d}{h}

a = \dfrac{9.8\times 0.78}{0.775}

a = 9.86 m/s²

4 0
3 years ago
Imagine a landing craft approaching the surface of Callisto, one of Jupiter's moons. If the engine provides an upward force (thr
nordsb [41]

Answer:

W=3456 N

Explanation:

Force 1 F_1=3456

Force 2 F_2=2333N

Acceleration at stage 2 a_2=0.39

Generally the weight of the Craft W is given as

W= upward force(thrust)

Therefore

W=3456 N

5 0
3 years ago
One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large
svet-max [94.6K]

Given:

• Mass, m = 0.200 mg

,

• Speed, v = 3.00 x 10³ m/s

,

• Time, t = 6.00 x 10^⁻⁸ s.

Let's calculate the force exerted.

Using the inpulse-momentum theroerm, we have:

impulse = change in momemntum

Where:

Impulse = force x time

change in momentum = mass x velocity.

Thus, we have:

F\times6.00\times10^{-8}=(0.200\times10^{-6})\times(3.00\times10^3)

Let's solve for the force F:

\begin{gathered} F=\frac{(0.200\times10^{-6})(3.00\times10^3)}{6.00\times10^{-8}} \\  \\ F=10000N \end{gathered}

Therefore, the force exterted is 10000 N.

ANSWER:'

10000 N

4 0
1 year ago
We wish to determine the electric field at a point near a positively charged metal sphere (a good conductor). We do so by bringi
quester [9]

Answer:

Less than.

Explanation:

We have the positive charged metal sphere and we have to determine the electric field at a point near to it. In order to find that if we bring the positive test charge at that point then as we know that "like charges repel" so their electric field lines will repel each other resulting in a weaker electric field.    

    However if we bring the negative test charge at that point then of course there will be attraction and also the the electric field lines will direct from the positive to negative resulting in a stronger electric field between them. So there will be larger electric field then before.

"In this case, It can be concluded that electric field will be less than it was at this point before the test charge was present."

5 0
3 years ago
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