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3 years ago

The atomic number of oxygen, 8 indicates that there are eight what???

2 answers:

6 0

The atomic number organizes the elements and also tells you how many protons there are in an element. So, oxygen would have 8 protons. The atomic number of oxygen 8 indicates that there are eight protons.

Hope this helps! (If correct rank as brainliest answer :)

Strike441 [17]3 years ago

4 0

The answer is A. The atomic number of an element is the number of protons in its nucleus.
Hope this helps

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Which form of heat transfer occurs when objects of two temperatures touch

Arada [10]

Conducting because it occurs when two objects touch and heat is transferred

7 0

3 years ago

An unusual fog that is denser than air begins to fill a room. Should the people in the room walk out or crwl out? The people sho

horsena [70]

Walk out. If it's denser than air, it'll settle to the bottom

8 0

3 years ago

A 2 m tall, 0.5 m inside diameter tank is filled with water. A 10 cm hole is opened 0.75 m from the bottom of the tank. What is

valina [46]

Answer:

4.75 m/s

Explanation:

The computation of the velocity of the existing water is shown below:

Data provided in the question

Tall = 2 m

Inside diameter tank = 2m

Hole opened = 10 cm

Bottom of the tank = 0.75 m

Based on the above information, first we have to determine the height which is

= 2 - 0.75 - 0.10

= 2 - 0.85

= 1.15 m

We assume the following things

1. Compressible flow

2. Stream line followed

Now applied the Bernoulli equation to section 1 and 2

So we get

$\frac{P_1}{p_g} + \frac{v_1^2}{2g} + z_1 = \frac{P_2}{p_g} + \frac{v_2^2}{2g} + z_2$

where,

P_1 = P_2 = hydrostatic

z_1 = 0

z_2 = h

Now

$\frac{v_1^2}{2g} + 0 = \frac{v_2^2}{2g} + h\\\\V_2 < < V_1 or V_2 = 0\\\\Therefore\ \frac{v_1^2}{2g} = h\\\\v_1^2 = 2gh\\\\ v_1 = \sqrt{2gh} \\\\v_1 = \sqrt{2\times 9.8\times 1.15}$

= 4.7476 m/sec

= 4.75 m/s

6 0

2 years ago

Which of the following accurately shows how to calculate the weight of a 20kg object

forsale [732]

The answer to your question is "20kgx9.8m/s" because weight is the force an object is exerting on another object, and the formula used to calculate force is <em>Force = Mass * Acceleration</em>.

4 0

3 years ago

Read 2 more answers

A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a d

Mnenie [13.5K]

Answer:

Explanation:

Given;

spring constant of the catapult, k = 10,000 N/m

compression of the spring, x = 0.5 m

mass of the launched object, m = 1.56 kg

Apply the principle of conservation of energy;

Elastic potential energy of the catapult = kinetic energy of the target launched.

¹/₂kx² = ¹/₂mv²

where;

v is the target's velocity as it leaves the catapult

kx² = mv²

v² = kx² / m

v² = (10000 x 0.5²) / (1.56)

v² = 1602.56

v = √1602.56

v = 40.03 m/s

v ≅ 40 m/s

Therefore, the target's velocity as it leaves the spring is 40 m/s

6 0

2 years ago