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omeli [17]
3 years ago
12

A 500 g ball swings in a vertical circle at the end of a 1.4-m-long string. when the ball is at the bottom of the circle, the te

nsion in the string is 18 n.
Physics
1 answer:
sergij07 [2.7K]3 years ago
6 0

A 500 g ball swings in a vertical circle at the end of a 1.4-m-long string. when the ball is at the bottom of the circle, the tension in the string is 18 n.

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How much kinetic energy is in a punch thrown at 30 m/s? The fist and arm weighs 6 lbs. (1 lb= 2.2 kg)
zvonat [6]

Answer:

5940J

Explanation:

KE = 1/2 mv²

KE = 1/2 13.2 * 30²

KE = 6.6*900

KE = 5940J

3 0
3 years ago
1 example of Deionization
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For example, the rain water does not have any salinity, except the small quantity due to the atmosphere, while the sea water has a very high salinity.

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7 0
3 years ago
On which principal is the thermometer based​
olchik [2.2K]

Answer:

thermometer is based on the principle of thermal expansion.

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3 years ago
Objects that are not moving have NO _____. A. mass (only) B. mass and momentum (only) C. velocity and momentum (only) D. mass, v
shepuryov [24]

Answer:

Objects that are not moving have NO velocity and momentum (only)

Explanation:

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6 0
2 years ago
A small charged bead has a mass of 3.6 g. It is held in a uniform electric field E = (200,000 N/C, up). When the bead is release
DiKsa [7]

Answer:

The charge on the bead is  q = 6.084 *10^{-7}\ C

Explanation:

From the question we are told that

     The  mass of the bead is  m  =  3.6 \ g =  0.0036 \ kg

      The  magnitude of the electric field is  E =  200,000 \ N/C

       The  acceleration of the bead is  a =  24 m/s^2

Generally,  the  electric force on the bead is  mathematically represented as  

         F_ e =  q E

Where q is the charge on the bead

   Now the gravitational force opposing the upward movement of the bead is  mathematically represented as

       F_g  =  mg

Generally the net force on the bead is  mathematically represented as

       F  =  F_e - F_g = m* a

=>    qE -  mg  = ma

Now substituting values

       q *  200000 -   0.0036 *9.8   = 0.0036 * 24

     q = 6.084 *10^{-7}\ C

6 0
3 years ago
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