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nalin [4]
4 years ago
8

How do scientists do background research on topics they have question about

Chemistry
1 answer:
Aliun [14]4 years ago
3 0
They use information from other things that relate to that topic and then use that to do their research
You might be interested in
A sample of methane occupies a volume of 370.0 ml at 25 oC and exerts a pressure of 1020 mm Hg. If the volume is allowed to expa
vagabundo [1.1K]

Answer:

744.9 mmHg ≅ 745 mmHg

Explanation:

The base to solve this, is the Ideal Gases Law. The mentioned formula is:

P . V = n . R . T

To compare two situations, we can propose:

For the first situation P₁ . V₁ = n₁. R . T₁

For the second situation P₂ . V₂ = n₂ . R . T₂

As the sample has the same moles and R is a constant value, we can avoid them so: (P₁ . V₁) / T₁ = (P₂ . V₂) / T₂

We need to make Tº unit conversion:

25ºC + 273 = 298K

We replace data → (370 mL . 1020 mmHg) / 298K = (P . 510 mL) / 300 K

(377400 mL.mmHg / 298K) . 300 K = P . 510 mL

379932.8 mL . mmHg = P . 510 mL

(379932.8 mL . mmHg) / 510 mL = P → 744.9 mmHg

7 0
3 years ago
Question 4 of 10
natka813 [3]

Answer:

Stalactites - Hang from caves ceilings

Stalagmites - Grow from cave floors

Sinkholes - Collapsed caves

Speleothems - Cave features

Explanation:

Got it right :)

8 0
2 years ago
And with solution...
Tems11 [23]

Answer:

The answer to your question is: V = 6.93 L

Explanation:

Data

N₂ = 5.6 g

Volume of NH₃ = ?

                              14 g of N   ----------------  1 mol

                              5.6 g -----------------------   x

                             x = (5.6 x 1) / 14 = 0.4 mol of N

Reaction

                                N₂    +     3H₂    ⇒    2NH₃

                                1 mol of N₂   ----------------  2 moles of NH₃

                                0.4 mol of N₂ --------------   x

                               x = (0.4 x 2) / 1

                               x = 0.8 mol of NH₃

Formula

                 PV = nRT

P = 5200 torr = 6.84 atm

V = ?

n = 0.8

R = 0.082 atm L/ mol °K

T = 450°C = 723°K

Substitution

                     V = (0.8)(0.082)(723) / 6.84

                     V = 6.93 L

7 0
3 years ago
C. 49.8 grams of ki is dissolved in enough water to make 1.00 l of solution. what is the molarity?
taurus [48]

Hey There!:


Molar Mass KI => 166.003 g/mol


* number of moles:


n = mass of solute / molar mass


n = 49.8 / 166.003


n = 0.3 moles KI


Therefore:


M = n / V


M = 0.3 / 1.00


M = 0.3 mol/L


hope this helps!

7 0
3 years ago
Read 2 more answers
Evidence of a chemical change would be
Elodia [21]
D- Rusting car fender
4 0
3 years ago
Read 2 more answers
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