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Norma-Jean [14]
3 years ago
10

Which of the following are not at equilibrium? Check all that apply. Check all that apply. The concentrations of reactants and t

he products are not constant. The rate of the forward reaction does not change. The rates of the forward and reverse reactions are equal.
Chemistry
1 answer:
tatyana61 [14]3 years ago
8 0

The concentrations of reactants and the products are not constant and the rates of the forward and reverse reactions are equal. and these reactions are not at equilibrium.

<u>Explanation:</u>

The conditions to attain equilibrium is that,

  • Conversion of reactant to product and vice versa occurs at the same rate.
  • The system is a closed system.
  • The temperature remains constant.
  • Concentration of every substance remains constant.
  • Rate of forward and reverse reactions will be different.

So the answer is The concentrations of reactants and the products are not constant and the rates of the forward and reverse reactions are equal.

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19) The nuclear symbol of helium,
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Answer:

Alpha particle

Explanation:

The helium symbol is also used to represent he alpha particles.

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The americium with atomic wight  224 undergo alpha decay and produce

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₉₅Am²²⁴   →    ₉₃Np²³⁷ + ₂He⁴

Properties of alpha radiation:

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Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

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4 0
3 years ago
Why do substances with weak intermolecular forces form solids at low melting points?
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To make any substance solid, molecules must come very close to each other. Substances with weak intermolecular forces have weak bonding. Hence to make their molecules come close to each other, we must provide low temperature. 
7 0
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PLEASE HELP ASAP!
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Answer:

\large \boxed{\text{D. 710 g}}

Explanation:

1. Calculate the molar mass of Na₂SO₄

\begin{array}{ccc}\textbf{Atoms} &\textbf{M}_{\textbf{r}} & \textbf{Mass/u}\\\text{2Na} & 23 & 46\\\text{1S} & 32 & 32\\\text{4O}&16 & 64\\&\text{TOTAL =} & \mathbf{142}\\\end{array}

The molar mass of Na₂SO₄ is 142 g/mol.

2. Calculate the moles of Na₂SO₄

\text{Moles of Na$_{2}$SO}_{4} = \text{2.5 L solution} \times \dfrac{\text{2.0 mol Na$_{2}$SO}_{4}}{\text{1 L solution}} = \text{5.0 mol Na$_{2}$SO}_{4}

3. Calculate the mass of Na₂SO₄

\text{Mass of Na$_{2}$SO}_{4} = \text{5.0 mol Na$_{2}$SO}_{4} \times \dfrac{\text{142 g Na$_{2}$SO}_{4}}{\text{1 mol Na$_{2}$SO}_{4}} = \text{710 g Na$_{2}$SO}_{4}\\\\\text{You need } \large \boxed{\textbf{710 g}} \text{ of Na$_{2}$SO}_{4}

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