Answer:
1. C. remains the same. 2. C. is less than Kc. 3. B. run in the reverse direction to reestablish equilibrium. 4. A. increase.
Explanation:
At constant temperature, the equilibrium concentration has not effect on the equilibrium constant because the rate constants do not change with change in the concentrations or amounts of the reactants or products. Change in the concentration of one reactant or product causes the concentration of the others to change so as to maintain a constant value for the equilibrium constant. On the other hand, the reaction quotient is used to measure the relative amounts of reactants and products during a chemical reaction at any point in time. The value of the reaction quotient shows the direction of the chemical reaction.
Therefore, when 0.31 moles of CCl4(g) are removed from the equilibrium system at constant temperature:
1. the value of Kc remains the same
2. the value of Qc is less than Kc
3. the reaction must run in the reverse direction to reestablish equilibrium
4. the concentration of 
will increase because product will be converted to reactants to reestablish equilibrium.
<h2>Phenocrysts and Porphyritic texture
</h2>
Explanation:
- The early formed crystals are of phenocrysts and the texture of these crystals is porphyritic texture.
- This crystallization occurs when early-forming plagioclase crystals which are rich in calcium start coating with plagioclase crystals which are rich in sodium.
- On cooling, the magma is then processed in a volcanic eruption, after the eruption the liquid which is left behind will start cooling and forms a porphyritic texture.
Answer:
bone loss and muscle deterioration
Explanation:
this helps the body keep thriving and bones strong and muscles in tact
In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
