Number 1: (A.)
Number 2: (A.)
Number 3: (B.)
I'm probably wrong but that is what i think
The answer is c because the calculations for the elements have to connect with the compounds
Answer:
B. 1.65 L
Explanation:
Step 1: Write the balanced equation
2 SO₂(g) + O₂(g) ⇒ 2 SO₃(g)
Step 2: Calculate the moles of SO₂
The pressure of the gas is 1.20 atm and the temperature 25 °C (298 K). We can calculate the moles using the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 1.20 atm × 1.50 L / (0.0821 atm.L/mol.K) × 298 K = 0.0736 mol
Step 3: Calculate the moles of SO₃ produced
0.0736 mol SO₂ × 2 mol SO₃/2 mol SO₂ = 0.0736 mol SO₃
Step 4: Calculate the volume occupied by 0.0736 moles of SO₃ at STP
At STP, 1 mole of an ideal gas occupies 22.4 L.
0.0736 mol × 22.4 L/1 mol = 1.65 L
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Answer:
8 mol of hydrogen will react with 1 mol of sulfur.
Explanation:
We'll begin by writing the balanced equation for the reaction.
This is given below:
8H2 + S8 —> 8H2S
Now, let us carefully observe the mole ratio of the reactants.
This is illustrated:
The mole ratio of the reactants ( i.e H2 and S8) is 8 : 1
From the balanced equation above,
We can thus, concluded that:
8 moles of H2 will reacted with 1 mole of S8.
