Which of these compounds would you expect to have the lowest melting point?
1 answer:
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From the reaction: <span>caco3(s) → cao(s) + co2(g) it can be seen that,
1 mol (i.e. 100 g) of CaCO3 gives 1 mol (i.e. 44 g) of CO2
Now, number of moles of CaCO3 present in reaction system,
</span>=
=
= 0.45 mol
So, 0.45 mol of CaCO3 will give 0.45 mol of CO2.
From ideal gas equation, we know that PV = nRT
V =
.
Given that, P = 645 torr = 0.8487 atm (Since, 1 atm = 760 torr)
Therefore, V =
= 34.8 l
1 mol (i.e. 100 g) of CaCO3 gives 1 mol (i.e. 44 g) of CO2
Now, number of moles of CaCO3 present in reaction system,
</span>=
=
So, 0.45 mol of CaCO3 will give 0.45 mol of CO2.
From ideal gas equation, we know that PV = nRT
V =
Given that, P = 645 torr = 0.8487 atm (Since, 1 atm = 760 torr)
Therefore, V =
= 34.8 l