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Ostrovityanka [42]
3 years ago
14

Look up sodium in the Periodic Table (Na). Then, answer the following questions

Chemistry
1 answer:
madreJ [45]3 years ago
4 0
There are 11 electrons in Sodium(Na)
The first shell can hold 2 electrons 
The second shell can hold 8 electrons 
The third shell can also hold 8 electrons but there is only 1 left

so the answer is 2, 8, 1 
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The reaction of ethane gas (C2H6) with chlorine gas produces C2H5Cl as its main product (along with HCl). In addition, the react
Kazeer [188]

Answer:

The percent yield of  chloro-ethane in the reaction is 82.98%.

Explanation:

C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl

Moles of ethane = \frac{300.0 g}{30 g/mol}=10 mol

Moles of chlorine gases =\frac{650.0 g}{71 .0 g/mol}=9.1549 mol

As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.

This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.

According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.

Then 9.1549 moles of chlorien gas will give:

\frac{1}{1}\times 9.1549 mol=9.1549 mol of chloro-ethane

Mass of 9.1549 moles of chloro-ethane:

9.1549 mol × 64.5 g/mol = 590.4910 g

Theoretical yield of  chloro-ethane: 590.4910 g

Given experimental yield of chloro-ethane: 490.0 g

\% Yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

\%Yield (C_2H_5Cl)=\frac{490.0 g}{590.4910 g}\times 100=82.98\%

The percent yield of  chloro-ethane in the reaction is 82.98%.

6 0
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Calculate the number of moles of C2H6 (nC2H6) in 1.80×1023 molecules of C2H6.
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What is the symbol beryllium is most likely to form ? and what kind of ion is it ?
zheka24 [161]

Answer:

Explanation:

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Beryllium is a divalent cation with a charge of +2.

It is capable of losing 2 electrons in order to be like the noble gas He and this is a more stable configuration.

7 0
3 years ago
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