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Nataly_w [17]
3 years ago
14

Why do substances with weak intermolecular forces form solids at low melting points?

Chemistry
1 answer:
Advocard [28]3 years ago
7 0
To make any substance solid, molecules must come very close to each other. Substances with weak intermolecular forces have weak bonding. Hence to make their molecules come close to each other, we must provide low temperature. 
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what was the purpose of running a tlc of ferrocene, the acetylferrocene product mixture, and co-spot (an overlay of ferrocene an
Mademuasel [1]

Answer:

a. All of the below

Explanation:

Column chromatography in chemistry is a chromatography method used to isolate a single chemical compound from a mixture.

TLC can be used to analyze a chemical reaction to determine if the reactants have been consumed and a new product has formed. Running a tlc of ferrocene, the acetylferrocene product mixture, and co-spot, when you view the TLC plate under a UV light, you will notice that acetylferrocene product is on the right-most lane, this shows that the reaction appears to be a success: the higher spot of ferrocene has been consumed), and a new product spot is present. From these we can observe that the we can use this to identify the number of products of the reaction, determine if the starting material is still present in the reaction and the elution in a chromatography column of the starting material and products. Therefore, all the choices are correct.

8 0
3 years ago
The molecular weight of a gas is ________ g/mol if 3.5 g of the gas occupies 2.1 l at stp
bija089 [108]
<span>Pre-1982 definition of STP: 37 g/mol Post-1982 definition of STP: 38 g/mol This problem is somewhat ambiguous because the definition of STP changed in 1982. Prior to 1982, the definition was 273.15 K at a pressure of 1 atmosphere (101325 Pascals). Since 1982, the definition is 273.15 K at a pressure of exactly 100000 Pascals). Because of those 2 different definitions, the volume of 1 mole of gas is either 22.414 Liters (pre 1982 definition), or 22.71098 liters (post 1982 definition). And finally, there's entirely too many text books out there that still use the 35 year obsolete definition. So let's solve this problem using both definitions and you need to pick the correct answer for the text book you're using. First, determine how many moles of gas you have. Just simply divide the volume you have by the molar volume. Pre-1982: 2.1 / 22.414 = 0.093691443 moles Post-1982: 2.1 / 22.71098 = 0.092466287 moles Now determine the molar mass. Simply divide the mass by the moles. So Pre-1982: 3.5 g / 0.093691443 moles = 37.35666667 g/mol Post-1982: 3.5 g / 0.092466287 moles = 37.85163333 g/mol Finally, round to 2 significant figures. So Pre-1982: 37 g/mol Post-1982: 38 g/mol</span>
5 0
4 years ago
Can someone help me?
Oduvanchick [21]

Answer:

<u>an element with a large number of valence electrons and a large atomic radius</u>

Explanation:

Electronegativity means a tedency when an atom attracts bonding electrons in a covalent bond situation.

» If an atom has many valency electrons [ <em>empty</em><em> </em><em>orbitals</em><em> </em><em>i</em><em>n</em><em> </em><em>o</em><em>u</em><em>t</em><em>e</em><em>r</em><em>m</em><em>o</em><em>s</em><em>t</em><em> </em><em>s</em><em>h</em><em>e</em><em>l</em><em>l</em><em> </em>], it has difficulty in attracting electrons hence electronegativity low.

» If an atom is large, its nuclear attraction force of incoming electrons is low hence low electronegativity.

.

7 0
3 years ago
What will be the pH of a buffer solution containing an acid of pKa7.5, with an acid concentration exactly one fourth of that of
I am Lyosha [343]

Answer: pH of buffer solution is 8.1

Explanation:

The formula for the Henderson–Hasselbalch equation is:

pH=pK_a+\log\frac{[A^-]}{[HA]}

pH is the concentration of [H^+]

pK_a is the acid dissociation constant,

A^- and HA are concentrations of the conjugate base and starting acid.

Putting in the values we get:

pH=7.5+\log\frac{x}{\frac{x}{4}}

pH=8.1

Thus pH of buffer solution is 8.1

3 0
3 years ago
The half-life of a certain element is 100 days. How many half-lives will it be before only one-eighth of this element remains?
Alexus [3.1K]
After 1 half life its half the element
after 2 hl its quarter remaining
after 3 hl its half the quarter which is 1 eighth
after 3 half lifes
6 0
3 years ago
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