Let us take the first equation first
2a + b = 5
Then
b = 5 - 2a
Now we have to put the value of b from the first equation in the second equation. Let us take the second equation now.
3a + 2b = 9
3a + 2(5 - 2a) = 9
3a + 10 - 4a = 9
- a = 9 - 10
- a = - 1
a = 1
Now let us put the value of a in the first equation.
2a + b = 5
2(1) + b = 5
2 + b = 5
b = 5 - 2
= 3
So the value of the unknown variable a is 1 and the value of the unknown variable b is 3.
To determine which of the following monomial function has a
maximum value, you have to assume the value of x. Let us say the value of x is
2. Substitute 2 for all x’s in the monomial function.
<span>y=-6x^3
= -6(2)^3 = -48
y=-5x^4 = -5(2)^4 = -80
y=5x^6 = 5(2)^6 = 320
y=6x^5 = 6(2)^5 = 192</span>
Therefore,
the monomial function with the maximum value is y = 5x^6
Answer:
10i and 7i
Step-by-step explanation:
Step 1: 198 ×
= 66, the number of men who left the party
Step 2: 256×
= 64, the number of women who left the party
66+64=130
Since 130 is the number of people that left, you would subtract it from the total number of people at the party originally.
198+256=454
454-130=325
So, 325 people are left at the party
