Answer:
Yes this compound could be shown to be butane, specifically, it can be shown to be 9 molecules of butane. Check Explanation for more.
Step-by-step explanation:
Butane contains 10 hydrogen atoms for every 4 carbon atoms. It's molecular formula is C₄H₁₀
The hydrocarbon compound presented has 36 carbon atoms and 90 hyfrogen atoms
If the ratio of each of these atoms present is also in the ratio 4:10 like C:H, then, it can be inferred that the compound is indeed Butane
C | H
36 | 90
dividing through by 9, we have
C | H
4 | 10
which is the exact ratio of Carbon to Hydrogen in butane.
Hence, the unknown compound is most likely 9 molecules of butane
9C₄H₁₀ = 36 carbon atoms and 90 hydrogen atoms.
Hope this Helps!!!
Answer:
20
Step-by-step explanation:
54 days!!!!!!!!!!!!!!!!!!!!!!!!!!!1
We can represent the problem as shown in the attached drawing
L1=x1
L2=x2
L=x------------distance of the center of mass
we have that
L1/L2=m2/m1------------------> L1*m1=L2*m2------------->m2=L1*m1/L2
moment = Md
the moment about O is defined to be
m1*L1+m2*L2=(m1+m2)*L
L=(m1*L1+m2*L2)/(m1+m2)
m1*L1+m2*L2=2*m1*L1--------remember-------------------->L1*m1=L2*m2
L=(2*m1*L1)/(m1+L1*m1/L2)
L=(2*m1*L1)/(m1*L2+L1*m1)/L2=(2*m1*L1)*L2/(L2*m1+L1*m1)
L=(2*L1*L2)/(L1+L2)
the coordinates of the center of mass are (L,0)
Answer:
ok so it basically means reducing a mixed number to its simplest form.
