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wel
4 years ago
13

How to solve n^2 + 10 - 8 + 80=0

Mathematics
2 answers:
Igoryamba4 years ago
6 0
What grade is this? !
OlgaM077 [116]4 years ago
5 0
Combine the constants into one:

n^2 + 88 = 0

This has two complex roots.

I suspect you may have meant n^2 + 10n + 78 = 0.

Double check the original problem and make any necessary corrections.

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A molecule of butane contains 10 atoms of hydrogen to every 4 atoms of hydrogen to every 4 atoms of carbon. Could a compound con
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Answer:

Yes this compound could be shown to be butane, specifically, it can be shown to be 9 molecules of butane. Check Explanation for more.

Step-by-step explanation:

Butane contains 10 hydrogen atoms for every 4 carbon atoms. It's molecular formula is C₄H₁₀

The hydrocarbon compound presented has 36 carbon atoms and 90 hyfrogen atoms

If the ratio of each of these atoms present is also in the ratio 4:10 like C:H, then, it can be inferred that the compound is indeed Butane

C | H

36 | 90

dividing through by 9, we have

C | H

4 | 10

which is the exact ratio of Carbon to Hydrogen in butane.

Hence, the unknown compound is most likely 9 molecules of butane

9C₄H₁₀ = 36 carbon atoms and 90 hydrogen atoms.

Hope this Helps!!!

8 0
3 years ago
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max2010maxim [7]

Answer:

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Step-by-step explanation:

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4 years ago
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The center of mass is defined as a point on the straight line between two objects with masses m1 and m2 such that L1 / L2 = M2 /
kondor19780726 [428]

We can represent the problem as shown in the attached drawing

L1=x1

L2=x2

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we have that

L1/L2=m2/m1------------------> L1*m1=L2*m2------------->m2=L1*m1/L2

moment = Md

the moment about O is defined to be

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L=(m1*L1+m2*L2)/(m1+m2)

m1*L1+m2*L2=2*m1*L1--------remember-------------------->L1*m1=L2*m2

L=(2*m1*L1)/(m1+L1*m1/L2)

L=(2*m1*L1)/(m1*L2+L1*m1)/L2=(2*m1*L1)*L2/(L2*m1+L1*m1)

L=(2*L1*L2)/(L1+L2)

the coordinates of the center of mass are (L,0)

4 0
3 years ago
What does <br><br>"mixed number in its lowest form." mean?
Viktor [21]

Answer:

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4 0
3 years ago
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