Using trial and error
x^4+5x^2-36 factors to (x-2)(x+2)(x^2+9)
2x^2+9x-5 factors to (x+5)(2x-1)
so
(x-2)(x+2)(x^2+9)(x+5)(2x-1)=0
set each to zero
x-2=0
x=2
x+2=0
x=-2
x^2+9=0
x^2=-9
x=3√-1
x=3i
x+5=0
x=-5
2x-1=0
2x=1
x=1/2=0.5
roots are
x=-5-2,0.5,2, and the imaginary root 3i
Answer: Choice B) 2^(-10) and 1/1024
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Explanation:
We'll use these two rules
Rule 1: (a^b)^c = a^(b*c)
Rule 2: a^(-b) = 1/(a^b)
Using rule 1 above, we can say
(2^5)^(-2) = 2^(5*(-2)) = 2^(-10)
So 2^(-10) is one of the answers
Now use rule 2 to convert 2^(-10) into...
2^(-10) = 1/(2^10) = 1/1024
so 1/1024 is the other answer
444!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
5
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
the answer is b because the they are only 5 numbers of student that check in for assignment details