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lana [24]
3 years ago
6

A painting crew reported that a job is 3/5 completed. What fraction of the job remains to be done?

Mathematics
2 answers:
Lunna [17]3 years ago
3 0

Answer:

2/5

Step-by-step explanation:

5/5 = full job

3/5  = done

full job - done =  remaining

5/5 job - 3/5 job

= 2/5 (remaining)

aleksandr82 [10.1K]3 years ago
3 0
<h2>Answer:</h2><h2></h2><h3>\frac{2}{5} is left to complete.</h3><h3></h3>

Step-by-step explanation:

To find out how much needs to be done, subtract the amount they got done by a whole fraction.

\frac{5}{5} - \frac{3}{5} = \frac{2}{5}

Feel free to let me know if you need more help. :)

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4 years ago
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gregori [183]

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4 0
4 years ago
Find parametric equations for the line through the point (0, 3, 2) that is parallel to the plane x + y + z = 5 and perpendicular
kozerog [31]
Hello : 
let A(0,3,2) and (Δ) this line , v vector   parallel to (<span>Δ).
M</span>∈ (Δ) : vector (AM) = t v..... t ∈ R

1 )    (Δ)  parallel to the plane x + y + z = 5 : let  : n an vector <span>perpendicular 
to the plane : n </span>⊥ v   ....   n(1,1,1) so : n.v =0  means : n.vector (AM) = 0
(1)(x)+(1)(y-3)+(1)(z -2) =0      ( vector (AM) = ( x, y -3 , z-2 )
x+y+z - 5=0 ...(1)

2)  (Δ) perpendicular to the line (Δ') : x = 1+t  , y = 3 - t , z = 2t :
vector (u) ⊥ v     .... vector(u) parallel to (Δ')  and vector(u) = (1 , -1 ,1)
vector (u) ⊥ vector (AM) means : 
(1)(x)+(-1)(y-3)+(2)(z -2) =0
x - y+2z - 1 = 0 ...(2)
so the system : 
x+y+z - 5=0 ...(1)
x - y+2z - 1 = 0 ...(2)
 (1)+(2) :   2x+3z - 6 =0
x = 3 - (3/2)z
subsct in (1) :    3 - (3/2)z  +y +z - 5 =0
y = 1/2z +2
let : z=t     
an parametric equations for the line (Δ) is :  x = 3 - (3/2)t
                                                                      y = (1/2)t +2
                                                                      z=t

verifiy : 
1) (Δ)  parallel to the plane x + y + z = 5 : 
(-3/2 , 1/2 ,1) <span>perpendicular to (1,1,1)
</span>because : (1)(-3/2)+(1)(1/2)+(1)(1) = -1 +1 = 0
2) (Δ) perpendicular to the line (Δ') :
 (-3/2 , 1/2 ,1) perpendicular to (1,-1,2)
because : (1)(-3/2)+(-1)(1/2)+(1)(2) = -2 +2 = 0
A(0, 3, 2)∈(Δ) : 
0 = 3-(3/2)t
3 = (1/2)t+2
2 =t
same :  t = 2

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3 years ago
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Furkat [3]

Step-by-step explanation:

\tan \theta =  \frac{3}{4}  \\  \\ \sec \theta =  \sqrt{1 +  { \tan }^{2} \theta}  \\  \hspace{22 pt} =  \sqrt{1 +  {( \frac{3}{4}  )}^{2} }  \\  \hspace{22 pt} =  \sqrt{1 +  {\frac{9}{16}  }}  \\ \hspace{22 pt} =  \sqrt{ {\frac{16 + 9}{16}  }}  \\  \hspace{22 pt} =  \sqrt{ {\frac{25}{16}  }}  \\ \red{  \boxed{\bold{ \therefore  \sec \theta  =  { {\frac{5}{4}  }} }}} \\  \\ \cos \theta  = \frac{1}{\sec \theta  }  =  \frac{4}{5}  =  \frac{a}{b}  \\   \\ \implies \: a = 4 \: and \: b = 5

6 0
4 years ago
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