The equation<span> of a </span>line<span> is typically written as </span>y<span>=mx+b where m is the </span>slope<span> and b is the </span>y<span>-intercept. If you a </span>point<span> that a </span>line passes through<span>, and its </span>slope<span>, this page will show you how to find the </span>equation<span> of </span>the line<span>. Fill the </span>point<span> that </span>the line passes through... ( , ) Example: (3,2<span>) ...and the </span>slope<span> of </span>the line. m= Example: m=<span>3, or ... hope this helpps!!!!</span>
Replace <span><span>f<span>(x)</span></span><span>fx</span></span> with <span>yy</span>.<span><span>y=<span><span>6<span>x3</span></span><span>−8</span></span></span><span>y=<span><span>6<span>x3</span></span><span>-8</span></span></span></span>Interchange the variables.<span><span>x=<span><span>6<span>y3</span></span><span>−8</span></span></span><span>x=<span><span>6<span>y3</span></span><span>-8</span></span></span></span>Solve for <span>yy</span>.
<span><span>y=<span><span>3<span>√<span>36<span>(<span>x+8</span>)</span></span></span></span>6</span></span><span>y=<span><span><span>36<span>x+8</span></span>3</span>6</span></span></span>Solve for <span>yy</span> and replace with <span><span><span>f<span>−1</span></span><span>(x)</span></span><span><span>f<span>-1</span></span>x</span></span>.
<span><span><span>f<span>−1</span></span><span>(x)</span></span>=<span><span>3<span>√<span>36<span>(<span>x+8</span>)</span></span></span></span><span>6</span></span></span>
Answer:
It would last for 3.2 days.
Step-by-step explanation:
100 men = 8 days
10 men = 0.8 days
60 men = 0.8 x 6 = 4.8 days
Now you subtract the days of 100 men and 60 men
8 - 4.8 = 3.2 days
Hope this helps!
Hello!
The formula for circumference is

and the formula for area of a circle is

. Armed with these formulas, we can begin to find the circumferences and areas of the circles.
20.
C =

C =

C =

C = 13(3.14)
C = 40.8
A =

A =

A =

A = 132.7
The circumference of the circle is 40.8 in and the area of the circle is 132.7 in².21.
[Since we are given the diameter for this problem, to find the circumference, we no longer need to multiply the radius by 2 as in

because the diameter is the radius × 2. For

we do need to divide the diameter by 2.]
C =

C = 49.3
A =

A =

A =

A = 193.5
The circumference of the circle is 49.3 in and the area of the circle is 193.5 in².
And that is all there is to it. I hope this helps you! (: