Answer:
T=138 °C
Explanation:
Given that
m = 0.028 kg
Net work output W= 60 KJ
T₂=2T₁
As we know that efficiency of Carnot heat engine given as
η = 0.5
We know that
Qa=heat addition
W= net work output
Qa= 120 KJ
From first law
Qa= W+ Qr
Qr= 120 - 60
Qr= 60 KJ
Qr Is the heat rejection.
Heat rejection per unit mass
Qr=60 / 0.028 = 2142.85 KJ/kg
Qr= 2142.85 KJ/kg
Temperature at which latent heat of steam is 2142.85 KJ/kg will be our answer.
T=138 °C
The temperature corresponding to 2142.85 KJ/kg will be 138 °C.
T=138 °C
Answer:
<em>screw thrust = ML</em><em> </em>
Explanation:
thrust of a screw propeller is given by the equation = p x Re
where,
D is diameter
V is the fluid velocity
p is the fluid density
N is the angular speed of the screw in revolution per second
Re is the Reynolds number which is equal to puD/μ
where p is the fluid density
u is the fluid velocity, and
μ is the fluid viscosity = kg/m.s = M
<em>Reynolds number is dimensionless so it cancels out</em>
The dimensions of the variables are shown below in MLT
diameter is m = L
speed is in m/s = L
fluid density is in kg/ = M
N is in rad/s = L =
If we substitute these dimensions in their respective places in the equation, we get
thrust = M
= M
<em>screw thrust = ML</em><em> </em>
This is the dimension for a force which indicates that thrust is a type of force
Answer:
note:
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