Answer:
The circuit is shown in my attachments, please take a good look
Answer:
To four significant digits = 2097 psi
Explanation:
<u>Applying the rule of thumb </u>
σ = Mc/I ---- ( 1 )
M = 1835 Ibf in , I/c = 0.875 in^3
∴ c/l = 1 / 0.875 = 1.1429
back to equation 1
σ = 1835 * 1.1429 = 2097.2215 psi
To four significant digits = 2097 psi
Answer:
Q = 5.06 x 10⁻⁸ m³/s
Explanation:
Given:
v=0.00062 m² /s and ρ= 850 kg/m³
diameter = 8 mm
length of horizontal pipe = 40 m
Dynamic viscosity =
μ = ρv
=850 x 0.00062
= 0.527 kg/m·s
The pressure at the bottom of the tank is:
P₁,gauge = ρ g h = 850 x 9.8 x 4 = 33.32 kN/m²
The laminar flow rate through a horizontal pipe is:


Q = 5.06 x 10⁻⁸ m³/s
Answer:

Explanation:
The question is: <em>Find the magnitude of the centripetal acceleration of the star with mass m₂</em>
The <em>centripetal acceleration</em> is the quotient of the centripetal force and the mass.

Thus, you can write the equations for each star:


As per Newton's third law, the centripetal forces are equal in magnitude. Then:

Now you can clear
:

Answer
See explanation for step by step procedures towards getting answers
Explanation:
Given that;
A fluid flows along the x axis with a velocity given by V = (xt) i ˆ, where x is in feet and t in seconds. (a) Plot the speed for 0 ≤ x ≤ 10 ft and t = 3 s. (b) Plot the speed for x = 7 ft and 2 ≤ t ≤ 4 s. (c) Determine the local and convective acceleration. (d) Show that the acceleration of any fluid particle in the flow is zero. (e) Explain physically how the velocity of a particle in this unsteady flow remains constant throughout its motion.
See attachments for further explanations