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Ivahew [28]
3 years ago
11

As an engineer who has just finished taking engineering materials course, your first task is to investigate the causes of an aut

omobile accident. Your findings show that the right rear wheel has broken off at the axle. The axle is bent. The fracture surface reveals a Chevron pattern pointing toward the surface of the axle. Suggest a possible cause for the fracture and why?
Engineering
1 answer:
SIZIF [17.4K]3 years ago
3 0

Answer is given below

Explanation:

  • Evidence shows that the axle was not broken before the accident, while the clumsy axle meant that the wheel was still attached when the load was applied.
  • This indicates that the Chevron prototype wheel suffered a severe impact shock, which caused the failure of the transmission to the axle. Preliminary evidence suggests that the driver lost control and crashed.
  • Further examination of the surface, microstructure and structure and characteristics of the fracture can be modified if the axle is properly prepared
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Consider a cubic crystal with the lattice constant a. Complete the parts (a)-(c) below. (a) Sketch the crystallographic planes w
Anna [14]

Answer:

(a) See attachment

(b) The two planes are parallel because the intercepts for plane [220] are X = 0,5 and Y = 0,5 and for plane [110] are X = 1 and Y = 1. When the planes are drawn, they keep the same slope in a 2D plane.

(c) d = \frac{a}{\sqrt{h^{2} + k^{2} + l^{2}}} = \frac{1}{\sqrt{2}} =   0,707

Explanation:

(a) To determine the intercepts for an specific set of Miller indices, the reciprocal intercepts are taken as follows:

For [110]

X = \frac{1}{1} = 1; Y = \frac{1}{1} = 1; Z = \frac{1}{0} = \inf.

For [220]

X = \frac{1}{2} = 0,5;Y = \frac{1}{2} = 0,5;Z = \frac{1}{0} = \inf.

The drawn of the planes is shown in the attachments.

(b) Considering the planes as two sets of 2D straight lines with no intersection to Z axis, then the slope for these two sets are:

For (1,1):

K_1 = \frac{1}{1} = 1

For (0.5, 0.5):

K_2 = \frac{0.5}{0.5} = 1

As shown above, the slopes are exactly equal, then, the two straight lines are considered parallel and for instance, the two planes are parallel also.

(c) To calculate the d-spacing between these two planes, the distance is calculated as follows:

The Miller indices are already given in the statement. Then, the distance is:

\frac{1}{d^{2}} = \frac{h^{2} + k^{2} + l^{2}}{a^{2}}

d = \frac{a}{\sqrt{h^{2} + k^{2} + l^{2}}} = \frac{1}{\sqrt{2}} =   0,707

7 0
3 years ago
Ammonia enters the expansion valve of a refrigeration system at a pressure of 10 bar and a temperature of 20oC and exits at 3.0
icang [17]

Answer:

Ammonia enters the expansion valve of a refrigeration system at a pressure of 10 bar and a temperature of 20 o C and exits at 5.0 bar. The refrigerant undergoes a throttling process. Determine the temperature, in o C, and the quality of the refrigerant at the exit of the expansion valve.

Explanation:

3 0
3 years ago
What chemicals go into lake michigan
solniwko [45]

Answer:

They include PCBs, dioxins, furans, hexachlorobenzene, benzo(a)pyrene (one of many polyaromatic hydrocarbons or PAHs), lead and mercury compounds and pesticides (toxaphene, mirex, aldrin/dieldrin, DDT). 3 Great Lakes Water Quality Agreement Work Group Report on Chemicals of Emerging Concern, August 2009.

7 0
4 years ago
Read 2 more answers
Tech A says that to read amperage, the meter must be hooked up in series in a circuit. Tech B says that to read amperage at a lo
Dovator [93]

Answer:

747464646647477565756t6565665664674646465765

7 0
4 years ago
Given that the company "Slate Rock and Gravel" has business locations in Granitetown and Bedrock, suppose that the company has b
kotegsom [21]

Answer:

Check the explanation

Explanation:

As Granitetown requires 5000 IP address and the starting IP address is 192.172.0.0 , we have to perform subnetting using number of hosts required

Number of IP address required by Granitetown=4000

Number of hosts bits =

2n -2= 5000

n=13 (approximately)

Number of hosts bits are 13 therefore subnet prefix =(32-13)=19

We have used 32 because IP address is of 32-bit

Subnet mask corresponding to /19 = 255.255.224.0

Starting IP address (given)= 192.172.0.0

Now to calculate last IP address of the subnet, OR operation will be performed between First IP address of the subnet and !Netmask

First IP address of subnet ( in binary) =

11000000.10101100.00000000.00000000

OR

00000000.00000000.00011111.11111111 (!Netmask)

11000000.10101100.000 11111.11111111 (result)

Converting result into decimal gives IP address 192.172.31.255 which will be the broadcast IP address of the subnet therefore

Last usable IP address = 192.172.31.254

Now, bedrock requires 2000 IP address

Therefore number of host bits are =

2n -2 =2000

n=10 (approximately)

Number of hosts bits required are 10

Therefore Netmask prefix = (32 -10) =22

Now, using the next subnet for bedrock therefore the first IP address of subnet will be 192.172.32.0

Now, similarly calculating last IP address of subnet

First IP address in binary =

11000000.10101100.00100000.00000000

OR

00000000.00000000.00000011.11111111 (!Netmask)

11000000.10101100.00100011.11111111 (result)

Now, result in decimal = 192.172.35.255

Therefore ,

Broadcast address of subnet =192.172.35.255

Last usable IP address =192.172.35.254

8 0
4 years ago
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