Answer:
a)W=12.62 kJ/mol
b)W=12.59 kJ/mol
Explanation:
At T = 100 °C the second and third virial coefficients are
B = -242.5 cm^3 mol^-1
C = 25200 cm^6 mo1^-2
Now according isothermal work of one mole methyl gas is
W=-
a=
b=
from virial equation
And
a=
b=
Now calculate V1 and V2 at given condition
Substitute given values = 1 x 10^5 , T = 373.15 and given values of coefficients we get
Solve for V1 by iterative or alternative cubic equation solver we get
Similarly solve for state 2 at P2 = 50 bar we get
Now
a=241.33
b=30780
After performing integration we get work done on the system is
W=12.62 kJ/mol
(b) for Z = 1 + B' P +C' P^2 = PV/RT by performing differential we get
dV=RT(-1/p^2+0+C')dP
Hence work done on the system is
a=
b=
by substituting given limit and P = 1 bar , P2 = 50 bar and T = 373 K we get work
W=12.59 kJ/mol
The work by differ between a and b because the conversion of constant of virial coefficients are valid only for infinite series
Answer:Science is the body of knowledge that explores the physical and natural world. Engineering is the application of knowledge in order to design, build and maintain a product or a process
Explanation:
Answer:
And Im still going with B..
Answer:
0.577
Explanation:
Answer:
Explanation:
Parameters given:
Angle = 30°
Mass of block = 5kg
Velocity = 6 m/s
Time = 4s
Frictional force is given in terms of Normal force as:
F = uN
Where u = coefficient of frictional force
N = normal force
Frictional force is given as:
F = mgsinθ
Normal force is given as:
N = mgcosθ
Coefficient of friction is therefore given as:
mgsinθ = u * mgcosθ
=> u = sinθ / cosθ
u = tanθ
u = tan(30°)
u = 0.577