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AURORKA [14]
3 years ago
13

Last year at a certain high school, there were 100 boys on the honor roll and 84 girls on the honor roll. This year, the number

of boys on the honor roll increased by 17% and the number of girls on the honor roll increased by 25%. By what percentage did the total number of students on the honor roll increase? Round your answer to the nearest tenth (if necessary).
Mathematics
1 answer:
stira [4]3 years ago
8 0

Answer:

The percent of boys and girls that naden it to the honor roll increased by 27 percent (27%)

Step-by-step explanation:

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g "They hired an analyst who collected a random sample of 40,361 Game of Thrones fans, and found that 8,337 of those fans said t
Viktor [21]

Answer:

The lower bound for a 90% confidence interval is 0.2033.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 40361, \pi = \frac{8337}{40361} = 0.2066

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2066 - 1.645\sqrt{\frac{0.2066*0.7934}{40361}} = 0.2033

The lower bound for a 90% confidence interval is 0.2033.

6 0
3 years ago
Given: △KLM, LM=20 3 <br> m∠L=105°, m∠M=30°<br> Find: KL and KM
Yuki888 [10]

Answer:


Step-by-step explanation:

Split the triangle into a 30-60-90 triangle. Since you have LM from that triangle, you can figure out the other sides. Then, using the leg from that triangle, the one next to it is a 45-45-90 triangle, meaning it's isosceles.

KM = 30 + 10√3

KL = 10√6


3 0
3 years ago
Solve: |x+2|=3<br><br> Can someone explain how to do this
katovenus [111]

Hey there!

ORIGINAL EQUATION:
|x + 2| = 3

TRANSLATE:

x + 2 = 3 or x + 2 = -3


SOLVING for: x + 2 = 3

SUBTRACT 2 to BOTH SIDES

x + 2 - 2 = 3 - 2

CANCEL out: 2 - 2 because it give you 1

KEEP: 3 - 2 because help solve for the current x-value

NEW EQUATION: x = 3 - 2

SIMPLIFY IT!
x = 1


Thus, your answer is: x = 2

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\


SOLVING for: x + 2 = -3

SUBTRACT 2 to BOTH SIDES

x + 2 - 2 = -3 - 2

CANCEL out: 2 - 2 because it give you 0

KEEP: -3 - 2 because it help solve for the current x-value

NEW EQUATION: x = -3 - 2

SIMPLIFY IT!
x = -5

Thus, your answer is: x = -5

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\


Therefore, your answer is: x = 1 or x = -5


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

6 0
2 years ago
When a sprinkler is installed in the ground, the spray of water goes up and falls in the pattern of a parabola. The height, in i
Westkost [7]

Answer:

(1) 256 inches

(2) 5 feet

(3) 400 inches

(4) 10 feet

Step-by-step explanation:

(1) The function that gives the height in inches of the spray of water at a distance <em>x</em> from the sprinkler head is given as follows;

h(x) = 160·x - 16·x²

At x = 2 feet, we have;

h(2) = 160 × 2 - 16 × 2² = 256

Therefore, the height of the spray water at a horizontal distance of 2 feet from the sprinkler head h(2) = 256 inches

(2) The x-coordinate, x_{max}, of the maximum point of a parabola given in the form, y = a·x² + b·x + c is found using the following formula;

x_{max} = -b/(2·a)

The x-coordinate, x_{max}, of the maximum point of the given equation of the parabola, h(x) = 160·x - 16·x², (a = -16, b = 160) is therefore;

x_{max} = -160/(2 × (-16)) = 5

Therefore, the number of feet along the way, the function will reach maximum height, x_{max} = 5 feet

(3) The function, h(x) = 160·x - 16·x², will reach maximum height, h_{max}, at x = 5, therefore;

h_{max} =  h(5) = 160 × 5 - 16 × 5² = 400

The maximum height of the spray, h_{max} = 400 inches

(4) The water is at ground level where h(x) = 0, therefore;

At ground level, h(x) = 0 = 160·x - 16·x²

160·x - 16·x² = 0

∴ 16·x × (10 - x) = 0

By zero product rule, we 16·x = 0, or (10 - x)  = 0, from which we have;

x = 0, or x = 10

The water is at ground level at x = 0 and x = 10 feet, therefore, the water will hit the ground again (the second time after leaving the sprinkler head at x = 0) at x = 10 feet.

7 0
3 years ago
5.7q-5.9-5.6q=-0.9q-2.2​
Harman [31]
The answer to the question

7 0
3 years ago
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