Answer:
16.54 mL
Explanation:
From the question;
- Density of mercury of 13.6 g/mL
- Mass of the mercury metal is 225 g
We are needed to determine the volume of the mercury metal;
We need to know that;
- Density is given by dividing the mass of a substance by its volume.
That is;
Density = Mass ÷ Volume
Rearranging the formula;
Volume = Mass ÷ Density
Therefore;
Volume = 225 g ÷ 13.6 g/mL
= 16.54 mL
Thus, the volume of the mercury needed is 16.54 mL
Answer:
option A= pH = 0.1
Explanation:
Given data:
Concentration of H₃O⁺ = 0.8 M
pH = ?
Solution:
pH = -log [H₃O⁺] H₃O⁺ = H⁺
pH = -log [0.8]
pH = - (-0.097)
pH = + 0.1
Answer:1)1.99 M
Explanation:
Molarity is given as = moles solute/Liter solution
The solute which is LiOH is already given in moles as 1.495 moles
Given that solution is 750 mL, we convert to liters.
Liters of the solution= mL of the solution x (1 L/1000 mL)
750 mL x (1 L/1000 mL)
0.75 L
Molarity = moles solute/Liter solution
Molarity = 1.495 moles of LiOH/0.75 L of solution
Molarity = 1.99M
The molarity of this solution is 1.99M (moles per liter).
