Answer:
F = 33.12 N
Explanation:
given,
first force = 15 N is oriented at 58.0° counterclockwise
second force = (−19.0 N,18.5 N)
x-component of first force = 15 cos 58.0° = 7.95 N
y-component of second force = 15 sin 58.0° = 12.72 N
second component
now,
F netx = 7.95 - 19 = -11.05 N
F nety = 12.72 + 18.5 = 31.22 N
F = 33.12 N
θ = -70.51°
Answer:
greater than 0.10
Explanation:
The null hypothesis is:
The alternate hypotesis is:
Our test statistic is:
In which X is the statistic, is the mean,
is the standard deviation and n is the size of the sample.
We have that:
We are testing if X is greater than 0.45, so our pvalue is 1 subtracted by the pvalue of z = t = 0.45.
z = 0.45 has a pvalue of 0.6736
1 - 0.6735 = 0.3264
So our pvalue is 0.3264, which is greater than 0.10.
So the correct answer is:
greater than 0.10