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S_A_V [24]
3 years ago
9

List some reasons why growth characteristics are more useful on agar plates than on agar slants

Physics
2 answers:
SpyIntel [72]3 years ago
5 0
Usually, in culturing of the bacteria we have a slant and then portion f it is transferred to the agar plate. The growth characteristics are more useful in the agar plates because it is where we really do the observation because bacteria in slants are still to be transferred in the agar plates. 
joja [24]3 years ago
3 0

Answer:

There are the few reasons for growth characterization are more useful on agar plates than on agar slant are discussed below.

Explanation:

Generally, agar plates are very larger and streaking out the bacteria can be possible in it. By doing this, you can find the analyzation of individual colonies of their morphology with the other uses.

  • Agar slants are usually used for the short time period of  stock cultures of bacteria.
  • Agar slants can be usually used to find the motility of bacteria by doing a single steak inoculation up the center of slant.
  • Agar plates are used used in stock cultures growing that can be refrigerated after the incubation and for several weeks it can be maintained.
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Which of the following statements apply to electric charges?
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Answer:

The statement "If a positively charged rod is brought close to a positively charged object, the two objects will repel " applies to electric charges.

Explanation:

There are only two types of electric charges. Both having own magnitude but different charge.

1. Positive charge

2. Negative charge

Like charges repel each other and opposite charges always attract each other.

When a positively charged rod is brought close to a positively charged object, the rod and the object will repel.

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As an object falls:
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c it is not accelerating on it's on but gravity pulls it there for velocity increases.

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A 150kg person stands on a compression spring with spring constant 10, 000 N/m and norminal.Length of 0.50.What is the togal len
Eva8 [605]

Answer:

Total length of spring 0.647 m

Explanation:

We have given mass of the person m = 150 kg

Acceleration due to gravity g=9.8m/sec^2

Spring constant k = 10000 N/m

Nominal length of spring = 0.50

According to hook's law

mg=kx

150\times 9.8=10000\times x

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What is the frequency of a transverse wave ?​
yuradex [85]

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A metal wire is in thermal contact with two heat reservoirs at both of its ends. Reservoir 1 is at a temperature of 781 K, and r
andreev551 [17]

Answer:2.517 J/K

Explanation:

Given

Reservoir 1 Temperature T_1=781 K

Reservoir 2 Temperature T_2=335 K

Let Q is the amount of heat Flows i.e. Q=1477 J

thus change in Entropy is given by \frac{\sum Q}{T}

\Delta S=\frac{\sum Q}{T}=-\frac{Q}{T_1}+\frac{Q}{T_2}

\Delta S=\frac{\sum Q}{T}=-\frac{1477}{781}+\frac{1477}{335}

\Delta S=\frac{\sum Q}{T}=-1.891+4.4089

\Delta S=\frac{\sum Q}{T}=2.517 J/K                              

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