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kiruha [24]
3 years ago
13

A box that has a mass of 80 kg slides down a ramp with a 30 degree angle. The free-body diagram shows the forces acting on the b

ox. Ignoring friction and air resistance, what is the acceleration of the box, to the nearest tenth? Answer choices are 0.5 m/s2 4.9 m/s2 8.5 m/s2 9.8 m/s2
Physics
2 answers:
zimovet [89]3 years ago
8 0
The first one I believe
Nonamiya [84]3 years ago
8 0

Answer:

a= 4.9 \frac{m}{s^{2} }

Explanation:

Force equation

F= m*a

F= W*g*sen (30)\\F= 80 kg * 9.8 \frac{m}{s^{2} } * sen (30)\\F= 80 kg * 9.8 \frac{m}{s^{2} } * 0.5\\F= 392  *\frac{kg*m}{s^{2} } = 392 N

a= \frac{F}{m} = \frac{392 N}{80 kg} = \frac{392 \frac{kg*m}{s^{2} } }{80 kg}\\ a= 4.9 \frac{m}{s^{2} }

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Imagine a system where a block rests on an inclined plane. The block is then given an initial push so that it starts sliding dow
Helen [10]

Answer:

statement - 'The work done by friction is equal to the sum of the work done by the gravity and the initial push' is correct.

Explanation:

The statement ''The work done by friction is equal to the sum of the work done by the gravity and the initial push" is correct.

The above statement is correct because, the initial push will tend to slide down the block thus the work done by the initial push will be in the downward direction. Also, the gravity always acts in the downward direction. thus, the work done done by the gravity will also be in the downward direction

here, the downward direction signifies the downward motion parallel to the inclined plane.

Now we know that the work done by the friction is against the direction of motion. Thus, the friction force will tend to move the block up parallel to the inclined plane.

Hence, for the block to stop sliding the the above statement should be true.

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