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julsineya [31]
3 years ago
13

Which acceleration graph corresponds to the pressure graph shown?

Physics
2 answers:
romanna [79]3 years ago
8 0

Answer:

Option B. Graph B

Explanation:

The graph B will be the correct option in this category. In essence, the pressure graph will be a sinusoidal wave. In this respect, the graph will be a wave-like function. This wave-like function will be identical at some point, having rising and falling areas. These areas may represent areas of compression and rarefaction. This is typical with sound waves which travel as pockets of alternating pressures. These compression and relaxations present a propagation in their movements.

rewona [7]3 years ago
3 0
Graph B
Hope it helps!
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Use the techniques to find the unit for speed​
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Answer:

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A small box of mass m1 is sitting on a board of mass m2 and length L. The board rests on a frictionless horizontal surface. The
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The constant force with least magnitude that must be applied to the board in order to pull the board out from under the box is \left( {{m_1} + {m_2}} \right){\mu _{\rm{s}}}

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{F_{\rm{f}}} = {\mu _{\rm{s}}}{m_1}g

Use the Newton’s second law for small box and solve for minimum acceleration aa to pull the box out.

Substitute  for , [/tex]{m_1}[/tex] for in the equation .

{F_{\rm{f}}} = {m_1}a

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{\mu _{\rm{s}}}{m_1}g = {m_1}a

Rearrange for a.

a = {\mu _{\rm{s}}}g

The minimum acceleration of the system of two masses at which box starts sliding can be calculated by equating the pseudo force on the mass with the maximum static friction force.

The pseudo force acts on in the direction opposite to the motion of the board and the static friction force on this mass acts in the direction opposite to the pseudo force. If these two forces are cancelled each other (balanced), then the box starts sliding.

Use the Newton’s second law for the system of box and the board.

Substitute for for in the equation .

{F_{\min }} = \left( {{m_1} + {m_2}} \right)a

Substitute for in the above equation .

{F_{\min }} = \left( {{m_1} + {m_2}} \right){\mu _{\rm{s}}}g

The constant force with least magnitude that must be applied to the board in order to pull the board out from under the box is \left( {{m_1} + {m_2}} \right){\mu _{\rm{s}}}g

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