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Zinaida [17]
3 years ago
8

What is the acceleration of a rocket that speeds up from 50 m/s to 1000 m/s in 3 seconds?

Physics
1 answer:
tresset_1 [31]3 years ago
6 0

Answer:

95 m/s^2

Explanation:

Givens

vi = 50 m/s

vf = 1000 m/s

t = 10 sec

a = ?

Equation

a = (vf - vi)/t

Solution

a = (1000 - 50)/10

a = 950/10

a = 95 m/s^2

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An important measure of LCD monitors is the time in milliseconds (ms) that it takes to turn a pixel on or off. What is this call
AleksandrR [38]

Answer:

Response Time

Explanation:

The time in milliseconds that LCD monitors takes to turn a pixel on or off is called Response time. A lower response time means that the LCD is able to cut down blurring or Ghosting of images thus producing better quality images.

Response time in general terms is the time interval that a system or a person takes to react to given input or event.

3 0
3 years ago
Can you guys please help me on this one?​
LenKa [72]

If the object is not at rest how?

4 0
2 years ago
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An object is 25.0 cm from the mirror, its height is 5.0 cm, and focal length is 8.0 cm. What is the distance from the image to t
Oksana_A [137]
1.) Use the formula to solve - 
             1/f = 1/do + 1/di; Where f = focal length; 1/do + 1/di
             1/f = 1/do + di
            1/8 = 1/25 + 1/?
          .125 = .04 + 1/di
   .125 -.04 = 1/di (transferred .04 to the left side of the equation)
       .085/1 = 1/di
.085di/.085 = 1/.085 (multiplied both sides by di and divided both sides by .085)
               di = 11.76 or 12
2.) Therefore, 12 cm is the distance from the image to the mirror
3 0
3 years ago
Read 2 more answers
During normal beating, a heart creates a maximum 3.95-mV potential across 0.305 m of a person’s chest, creating a 0.75-Hz electr
WINSTONCH [101]

Answer:

E = 0.0130 V/m.

Explanation:

The electric field is related to the potential difference as follows:

E = \frac{\Delta V}{d}

<u>Where:</u>

E: is electric field

ΔV: is the potential difference = 3.95 mV  

d: is the distance of a person's chest = 0.305 m

Then, the electric field is:

E = \frac{\Delta V}{d} = \frac{3.95 \cdot 10^{-3} V}{0.305 m} = 0.0130 V/m

Therefore, the maximum electric field created is 0.0130 V/m.

I hope it helps you!

7 0
3 years ago
What happens to the momentum of an object when velocity is kept the same and the mass is increased?
Jet001 [13]
Momentum = mass x velocity so if velocity is kept same and mass is increased then momentum will increase.
6 0
3 years ago
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