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Sergeeva-Olga [200]
3 years ago
11

What is the sum when the two decimals are added together

Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0

When you add decimals you dont add them

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Calculate 20% of R400​
Zinaida [17]

Answer:

<h2><u><em>80</em></u></h2>

Step-by-step explanation:

400: 100 you find 1% you multiply it by 20 and you have 20%

400 : 100 * 20 =

4 * 20 =                                    

<h2><u><em>80</em></u></h2>

                                       

6 0
3 years ago
Please help! I will mark you as brainliest!
mamaluj [8]

Answer:

Step-by-step explanation:

The purple circle, not ring is pi 7 squared = 153.93804

Then subtract the smaller circles area (pi 4 squared) = 153.9... - 103.6725576 =

50.2654824

Purple ring is 50.2654824

The entire circle is 4+3+3 (10) squared times pi = 314.1592654

( 50.2654824 / 314.1592654 ) x 100 = 15.999999998 %

4 0
3 years ago
In what quadrant would the ordered pair (-5, 4) be located?<br><br> I<br> II<br> III<br> IV
statuscvo [17]
Ok, so
 Quadrants are found on coordinate planes. So the first number tells you to go on the X axis. It goes this way ---------
you look on the left side side of the origin (zero) and go to -5
since the second umber will be found on the Y axis, and is positive, go up to 4.
That is how you find your point.  The qudrants are counted like this.
2 1 
3 4
The answer is Quadrant 2
Hope it helped☺
7 0
3 years ago
Solve the equation for x, and enter your answer below.<br>7 x -5= 65​
Sedaia [141]

x=10

Step-by-step explanation:

7x - 5=65

+5 +5 so the 5's cancel so add 5 to 65

7x =70 because you add 5 to 65 to get 70

7x 7

7 x cancels out so you answer will be

x=10

3 0
4 years ago
Read 2 more answers
Find the x-intercepts of the parabola with
12345 [234]

Answer:

x-intercepts are (0, 0) and (-6, 0)

Step-by-step explanation:

equation of a parabola in vertex form:  y = a(x - h)² + k

where (h, k) is the vertex

Substituting the given vertex (-3, -18) into the equation:

y = a(x + 3)² - 18

If the y-intercept is (0, 0) then substitute x=0 and y=0 into the equation and solve for a:

0 = a(0 + 3)² - 18

⇒ 0 = a(3)² - 18

⇒ 0 = 9a - 18

⇒ 9a = 18

⇒ a = 2

Therefore, y = 2(x + 3)² - 18

To find the x-intercepts, set the equation to 0 and solve for x:

                                 2(x + 3)² - 18 = 0

Add 18 to both sides:     2(x + 3)² = 18

Divide both sides by 2:    (x + 3)² = 9

Square root both sides:      x + 3 = ±3

Subtract 3 from both sides:  x = ±3 - 3

so x = 3 - 3 = 0  

and  x = -3 - 3 = -6

So x-intercepts are (0, 0) and (-6, 0)

8 0
2 years ago
Read 2 more answers
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