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Minchanka [31]
3 years ago
6

14

Mathematics
1 answer:
Arada [10]3 years ago
6 0

Answer:

Gerrard

Step-by-step explanation:

Let the size of each poster be x

Eve's poster portion painted will be

=\frac{1}{6}\times x\\=\frac{x}6}

Gerrard's painted portion will be:

=\frac{1}{5}\times x\\=\frac{x}{5}

From the two inequalities, we find that \frac{x}{5} is greater than \frac{x}{6}  by x/30

\frac{x}{5}-\frac{x}{6}\\=\frac{x}{30}\\

hence Gerrard has the larger blue section. His portion is 16.67% greater than Eve's

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1. The sum of the angles is 90° The difference between twice the larger angle and the smaller
Ostrovityanka [42]

Answer:

\displaystyle 25°\:and\:°65

Step-by-step explanation:

{90° = m∠1 + m∠2

{105° = 2m∠1 - m∠2

_______________

\displaystyle \frac{195°}{3} = \frac{3m∠1}{3} \\ \\ 65° = m∠1

All you have left to do is this:

\displaystyle 25° = -65° + 90°

So, your two angle measures are \displaystyle 25°\:and\:°65.

I am joyous to assist you anytime.

5 0
3 years ago
PLEASE HELP WITH GEOMETRY IM STUCK!?}
Ilya [14]

Answer:

13.8

Step-by-step explanation:

Recall the trigonometric ratios

Sine = Opposite over Hypotenuse (SOH)

Cosine = Adjacent over Hypotenuse (CAH)

Tangent = Opposite over Adjacent (TOA)

Now lets look back at the question

We are given an angle and its adjacent side length (11) and we need to find the hypotenuse

The hypotenuse and adjacent sides corresponds with the trig function cosine so we will use cosine to solve for x

( remember that cosine = adjacent over hypotenuse )

cos(37)=\frac{11}{x}

step 1 multiply each side by x

cos(37)*x=xcos(37)\\\frac{11}{x} *x=11

now we have xcos(37)=11

step 2 divide each side by cos(37)

\frac{xcos(37)}{cos(37)} =x\\\frac{11}{cos(37)} =13.77349\\

we're left with x = 13.77439

Our last step would be to round to the nearest tenth

We would get that the answer is 13.8

3 0
2 years ago
Read 2 more answers
in the cafeteria ,100 mike cartons were put out for breakfast.At the end of breakfast,27 remainded,what is the ratio of the numb
IgorC [24]
Number of cartons taken:
100 - 27 = 73
ratio of cartons taken : ratio of total cartons
73 : 100
5 0
3 years ago
How would I do question 5 I don’t understand
bazaltina [42]

Answer:

a) f(0)=4

b) f(-2)=2

c) x∈{-8,-4,4,8}

d) x∈{-9,-3,3,9}

e) x∈(-∞,-9)∪(-3,3)∪(9,∞).

f)  x∈[-9,-3]∪[3,9]

g) Domain is x∈[-10,10]. Range is y∈[-4,4]. Zeros are at elements of x in {-9,-3,3,9}

h) Increasing on x∈ (-6,0) ∪ (6,10) and

decreasing on x∈ (-10,-6) ∪ (0,6).

Step-by-step explanation:

a) f(0) means what is the y-coordinate of the point at x=0.

So find 0 on the x-axis. I'm going to go up because the curve is at y=4 there.

Conclusion: f(0)=4.

b) f(-2) means what is the y-coordinate of the point at x=-2.

So find -2 on the x-axis. I'm going to go up because the curve is at y=2 there.

Conclusion:  f(-2)=2.

c) f(x)=-2 means what is x when y=-2.  So go on the y-axis and find -2. Now anything on that line y=-2 (horizontal line going through y=-2 on the y-axis) we need to look at.

There are 4 value we need to look at then.

x=-8

x=-4

x=4

x=8

At all of these the y-coordinate is -2.

d) f(x)=0 means what is x when y=0.  So go on the y-axis and find 0. Now anything on that line y=0 (horizontal line going through y=0 on the y-axis; also knowing as the x-axis for y=0) we need to look at.

There are 4 values we need to look at then.

x=-9

x=-3

x=3

x=9

e)  f(x)>0 means where is the curve above the x-axis.

The curve is above the x-axis:

  • Before x=-9
  • Between x=-3 and x=3
  • After x=9

The interval notation is:

(-∞,-9)∪(-3,3)∪(9,∞).

d) f(x)≥0 means where is the curve below or on the x-axis (also known as y=0).

The curve is below or on the x-axis:

  • Between -9 and -3 (inclusive of both endpoints because they include y=0).
  • Between 3 and 9 (inclusive of both endpoints because they include y=0).

The interval notation is:

[-9,-3]∪[3,9]

g) The domain is where the curve exists for the x-values.

The domain is all real numbers between -10 and 10 (inclusive of both).

The curve starts at x=-10 and stops at x=10. The function exists a y value for any number between -10 and 10 (including both).

Interval notation is:

[-10,10]

The range is where the curve exists for the y-values.

Looking from bottom to top I see that it starts at y=-4 and stops at y=4. I notice the curve exists at some point between those two horizontal lines. It also exists at both of those endpoints" -4 and 4.

The range is between -4 and 4 (including both).

Interval notation is:

[-4,4]

The zeros are where the graph crosses the x-axis.

The graph crosses the x-axis at:

x=-9

x=-3

x=3

x=9

h)  Reading left to right the graph increases when you see the curve going up.

I see this from x=-6 to x=0 (exclusive of both).

I see this from x=6 to x=10 (exclusive of both).

So interval notation is (-6,0) ∪ (6,10).

Reading left to right the graph decreases when you see the curve going down.

I see this from x=-10 to x=-6 ( exclusive of both).

I see this from x=0 to x=6 (exclusive of both).

4 0
3 years ago
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Step-by-step explanation:

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