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Harman [31]
3 years ago
7

I know #2 is D. I just need to know why

Chemistry
2 answers:
Novosadov [1.4K]3 years ago
8 0
<h3>Explanation</h3>

The rate law depends on coefficients in the rate-determining step of this reaction (the slowest step). The equation A + 2 B → C represents the overall reaction. Finding the rate law requires experimental data.  

Compare row 1 and row 2:

  • [A]₀ is the same in row 2 and row 1;
  • [B]₀ is twice as much in row 2 as in row 1;
  • Rate of change in [C] is four times as much in row 2 as in row 1.
  • 2² = 4. As a result, the reaction is of second order with respect to B.

Compare row 1 and row 3:

  • [A]₀ is twice as much in row 3 as in row 1;
  • [B]₀ is the same in row 3 and row 1;
  • Rate of change in [C] is twice as much in row 3 as in row 1.
  • 2¹ = 2. As a result, the reaction is of first order with respect to A.

What would be the rate law of this reaction?

Rate = k · [A] · [B]².

Allushta [10]3 years ago
7 0

B^2 would not be b*2.

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What is the mass in grams of a pure iron cube that has a volume of 4.60 cm3
yuradex [85]
In order to determine the mass of a substance given the volume, we require the density. The density of iron is 7.87 grams/cm³

Now,

Density = mass / volume

Mass = density * volume

Mass = 7.87 * 4.6

36.2 grams of iron are present in the cube
5 0
3 years ago
Help pretty please :)
Hatshy [7]
The answer is 15 bc you multiply the coefficient but the subscript
4 0
3 years ago
A fine of 50.0 mL of 0.0900 M CaCl2 reacts with excess sodium carbonate to give 0.366 g of calcium carbonate precipitate. What i
In-s [12.5K]

Answer:

81.26% is the percent yield

Explanation:

Based on the reaction:

CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃

<em>Where 1 mole of CaCl₂ in excess of sodium carbonate produces 1 mole of calcium carbonate.</em>

<em />

To solve this question we must find the moles of CaCl2 added = Moles CaCO₃ produced (Theoretical yield). The percent yield is:

Actual yield (0.366g) / Theoretical yield * 100

<em>Moles CaCl₂ = Moles CaCO₃:</em>

0.0500L * (0.0900moles / L) = 0.00450 moles of CaCO₃

<em>Theoretical mass -Molar mass CaCO₃ = 100.09g/mol-:</em>

0.00450 moles of CaCO₃ * (100.09g / mol) = 0.450g of CaCO₃

Percent yield = 0.366g / 0.450g * 100

81.26% is the percent yield

3 0
3 years ago
Jumping on a cemented floor is more pain full than a sandy flour,why​
Anvisha [2.4K]

Answer:

Is soft

Explanation:

because concrete is hard ash so t hink flour would be safer

5 0
3 years ago
n a gas-phase equilibrium mixture of SbCl5, SbCl3, and Cl2 at 500 K, pSbCl5 = 0.17 bar and pSbCl3 = 0.22 bar. Calculate the equi
Lorico [155]

Answer:

2.7 × 10⁻⁴ bar

Explanation:

Let's consider the following reaction at equilibrium.

SbCl₅(g) ⇄ SbCl₃(g) + Cl₂(g)

The pressure equilibrium constant (Kp) is 3.5 × 10⁻⁴. We can use these data and the partial pressures at equilibrium of SbCl₅ and SbCl₃, to find the partial pressure at equilibrium of Cl₂.

Kp = pSbCl₃ × pCl₂ / pSbCl₅

pCl₂ = Kp × pSbCl₅ / pSbCl₃

pCl₂ = 3.5 × 10⁻⁴ × 0.17 / 0.22

pCl₂ = 2.7 × 10⁻⁴ bar

7 0
3 years ago
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