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Elena-2011 [213]

2 years ago

14

Which of the following is a form of electromagnetic waves? Alpha radiation Beta radiation Gamma radiation Gravity

1 answer:

patriot [66]2 years ago

8 0

Answer:

The correct answer is GAMMA RADIATION.

Explanation:

Electromagnetic waves are waves that are created as the result of the interaction between the magnetic and the electric field. Gamma ray is a type of electromagnetic wave, it has the shortest wavelength compare to other electromagnetic waves, thus, it has high penetrating power. Gamma ray is an ionizing radiation, which can be a source of biological hazard.

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The distance from Santa Maria to Los Alamos is 16.25 mi. what is the distance in meters?

Radda [10]

Answer:

26,167.47m

Explanation:

Problem:

We are to solve this problem using dimensional analysis:

from the given conversion factors-

0.621mi = 1.00km

1km = 1000m

From the problem, we are groing from miles to metres:

16.25mi x $\frac{1km}{0.621mi}$ x $\frac{1000m}{1km}$

The mi will cancel out and also the km. This leaves us with the desired unit we want which is meters, m.

= 26,167.47m

7 0

2 years ago

In which eukaryotic organelle are amino acids and fatty acids oxidized?

boyakko [2]

<span>centrosome
thylakoid
(peroxisome)
lysosome</span>

6 0

3 years ago

Can you give me more explanation in the picture?

PolarNik [594]

Read the paper more carefully if you don't understand it

5 0

2 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

Citrus2011 [14]

<u>Answer:</u> The mass of lead iodide produced is 9.22 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles$

The chemical equation for the reaction of NaI and lead chlorate follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = $\frac{1}{2}\times 0.04=0.02mol$ of lead iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

$0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g$

Hence, the mass of lead iodide produced is 9.22 grams

6 0

3 years ago

Manganese nodules are considered a valuable resource from the ocean floor because they are abundant and contain not only mangane

MAVERICK [17]

Answer: iron (oxides of iron)

Explanation: manganese nodules usually contain layers of iron and manganese oxides in a concentric arrangement and are called polymetallic nodules.

4 0

3 years ago