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3 years ago

Please help me balance:_NaNO3 + _PbO_ ➡️ Pb(NO3)2 + _Na2O

Chemistry

1 answer:

KengaRu [80]3 years ago

7 0

Answer:

The balanced reaction is given by,

$2NaN(O)3 + PbO$ ⇒ $Pb(NO3)2 + Na2O$

Explanation:

The reaction is as given.

Lets count the number of each elements in the reaction.

In reactant side, number of sodium atoms are 1 , lead are 1, nitrogen are 1 and oxygen are 4.

in product side, number of sodium atoms are 2 , lead are 1 , nitrogen are 2 and oxygen are 7.

So we need to balance sodium and oxygen atoms in the reaction.

There is deficient of sodium and oxygen atoms on reactant side.

Thus, multiply (NaNO3) by 2.

Thus, sodium atoms become 2 , nitrogen 2 and oxygen 6. Total 7 oxygen atoms.

Thus, the balanced reaction is,

$2NaN(O)3 + PbO$ ⇒ $Pb(NO3)2 + Na2O$

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Explanation:

1 mol of ZrSiO₄ , have , 1 mol of Zr , 1 mol of Si and 4 mol of Oxygen .

since ,

1 mol of a substance have 6.022 * 10 ²³ particles ,

From the question ,

0.3384 mol of zircon ZrSiO₄ ,

hence ,

from the above equation ,

1 mol of a substance have 6.022 * 10 ²³ particles ,

0.3384 mol = 0.3384 * 6.022 * 10 ²³ number of atoms

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Hence ,

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Hence ,

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number of atoms of Si = 0.3384 mol * 6.022 * 10 ²³ = 2.037 * 10 ²³ number of atoms

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The mass is calculated as -

since ,

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

n = w / m

w = n * m

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Since we know , the molecular mass of Zr = 91 g/mol

moles of Zr = 0.3384 mol

using the above formula ,

w = n * m

w = 0.3384 mol * 91 g/mol = 30.79 g

hence ,

The mass of Zr = 30.79 g

mass of Si ,

Since we know , the molecular mass of Si = 28 g/mol

moles of Si = 0.3384 mol

using the above formula ,

w = n * m

w = 0.3384 mol * 28 g/mol = 9.475 g

hence ,

The mass of Si = 9.475 g

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Since we know , the molecular mass of O = 16 g/mol

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using the above formula ,

w = n * m

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hence ,

The mass of O = 21.65 g

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