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3 years ago

Please help me balance:_NaNO3 + _PbO_ ➡️ Pb(NO3)2 + _Na2O

Chemistry

1 answer:

KengaRu [80]3 years ago

7 0

Answer:

The balanced reaction is given by,

$2NaN(O)3 + PbO$ ⇒ $Pb(NO3)2 + Na2O$

Explanation:

The reaction is as given.

Lets count the number of each elements in the reaction.

In reactant side, number of sodium atoms are 1 , lead are 1, nitrogen are 1 and oxygen are 4.

in product side, number of sodium atoms are 2 , lead are 1 , nitrogen are 2 and oxygen are 7.

So we need to balance sodium and oxygen atoms in the reaction.

There is deficient of sodium and oxygen atoms on reactant side.

Thus, multiply (NaNO3) by 2.

Thus, sodium atoms become 2 , nitrogen 2 and oxygen 6. Total 7 oxygen atoms.

Thus, the balanced reaction is,

$2NaN(O)3 + PbO$ ⇒ $Pb(NO3)2 + Na2O$

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Hydrochloric acid reacts with sodium hydroxide to produce sodium chloride and water. If 20.6 g of sodium hydroxide reacts with a

astraxan [27]

Answer:

30.1 g NaCl

Explanation:

Your first conversion is converting grams NaOH to moles of NaOH using its molar mass (39.997 g/mol). Then, use the mole ratio of 1 mol NaCl for every 1 mol NaOH to get to moles of NaCl. Then finally multiply by the molar mass of NaCl (58.44 g/mol) to get grams of NaCl.

20.6 g NaOH • (1 mol NaOH / 39.997 g NaOH) • (1 mol NaCl / 1 mol NaOH) • (58.44 g NaCl / 1 mol NaCl) = 30.1 g NaCl

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3 years ago

The quantum mechanical model of the atom

ollegr [7]

No two electrons in an atom can have exactly the same quantum numbers. Orbital quantum numbers tell you what energy level the electron is in. In the Bohrmodel, this represents how high the orbit is above the nucleus; higher orbits have more energy

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3 years ago

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The quantitative amount of charge separation in a diatomic molecule contributes to the dipole moment of that molecule. A. True B

SOVA2 [1]

Answer:

The answer is True.

Explanation:

The sentence above is true it all adds up.

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2 years ago

Calculate the total amount of energy required to change 10.0 g of water from 35.0 degrees Celsius to 110. degrees Celsius.

Makovka662 [10]

Answer:

The total amount of energy required is 25,515.2 J.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When a system absorbs (or gives up) a certain amount of heat, it can happen that:

experience a change in its temperature, which involves sensible heat,
undergoes a phase change at constant temperature, or latent heat.

To calculate the latent heat the formula is used:

Q = m. L

Where

Q: amount of heat
m: mass
L: latent heat

To calculate sensible heat the following formula is used:

Q = m. c. ΔT

where:

Q: amount of sensible heat
m: body mass
c: specific heat of the substance
ΔT: temperature range

In this case, you have in the first place a heat to raise the temp of the water from 35.0 C to 100 C, where the specific heat value for water is 4.184 $\frac{J}{g*C}$ :

q1 = m*c*(Tfinal-Tinitial)

q1 = 10.0 g *(4.184 $\frac{J}{g*C}$ )* (100 - 35.0 C) = 2719.6 J

Now you have the heat to vaporize the water, where the heat of vaporization is 2259.36 $\frac{J}{g}$ :

q2 = m*(heat of vaporization)

q2 = 10.0 g*(2259.36 $\frac{J}{g}$ ) = 22593.6 J

Finally, you have the heat to raise temp of steam to 110 C, where the specific heat value for steam is 2.02 $\frac{J}{g*C}$ :

q3 = m*c*(Tfinal-Tinitial)

q3 = 10.0 g*(2.02 $\frac{J}{g*C}$ )*(110-100 C) = 202 J

The total amount of energy can be calculated as:

Q= q1 + q2 + q3

Q= 2719.6 J + 22593.6 J + 202 J

Q=25,515.2 J

The total amount of energy required is 25,515.2 J.

5 0

3 years ago

The reaction ag+(aq) + cl−(aq) ↔ agcl(s) has an equilibrium of 1020 (keq = 1020). if you have a beaker containing 1 liter of wat

lord [1]

When Q is equal the initial concentration of the products / the initial concentration of the reactants.

so, Q = [Ag]*[Cl-] and we neglected [AgCl] as it is solid

∴ Q = 10^-6 * 10^-5

= 10^-11

now we will compare the value of Q with the value of Keq:

when Q = Keq so, the system is in equilibrium

and when Q > Keq so, the reaction will go forward (shift to right) to achieve equilibrium.

and when Q< Keq so, the reaction will go left (shift to left) to achieve equilibrium.

when Q = 10^-11 and Keq = 10^20

∴Q< Keq

and the reaction will shift to left.

3 0

3 years ago