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Montano1993 [528]
3 years ago
15

ΔH for the reaction below is -826.0 kJ/mol. Calculate the heat change when a 69.03-g sample of iron is reacted.4Fe(s) + 3 O2(g)

--> Fe2O3(s)a. - 255.2 kJb. -510.5 kJc. -1020.9 kJd. -2042 kJe. -2.851 x 10^4 kJ
Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

Answer:

c. -1020.9 kJ

Explanation:

4Fe (s) + 3 O₂ (g) --> 2 Fe₂O₃(s)         ΔH  =  -826.0 kJ/mol.

atomic weight of iron = 56

69.03 g = 69.03 / 56

= 1.23268 moles

Heat released by 1.23268 moles

= 1.23268 x 826.0

= -1020.9 kJ .

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Removal of the loosely bounded electron is defined by the ionization energy. Chlorine needs less energy to add electrons and has higher ionization power. Thus, option A is correct.

<h3>What is ionization energy?</h3>

The ability of an electron to accept or give electrons to another element in a chemical reaction by forming and creating bonds and the positive and negative charges has been defined by the ionization energy.

Magnesium has lower ionization energy than chlorine due to its large size and smaller nuclear charge. On the other hand, chlorine can easily add electrons to the valence shell which is almost full.

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1 year ago
What is the associated deBroglie wavelength of a H2 molecule moving on one direction with kinetic energy of (3/2 kT) at 30 K
andrey2020 [161]

<u>Answer:</u> The de-Broglie's wavelength of a hydrogen molecule is 3.26\AA

<u>Explanation:</u>

Kinetic energy is the measure of temperature of the system.

The equation used to calculate kinetic energy of a particle follows:

E=\frac{3}{2}kT

where,

E = kinetic energy of the particles  = ?

k = Boltzmann constant  = 1.38\times 10^{-23}J/K

T = temperature of the particle = 30 K

Putting values in above equation, we get:

E=\frac{3}{2}\times 1.38\times 10^{-23}J/K\times 30K\\\\E=6.21\times 10^{-22}J

  • Calculating the mass of 1 molecule of hydrogen gas:

Conversion factor used:  1 kg = 1000 g

1 mole of hydrogen gas has a mass of 2 grams or 2\times 10^{-3}kg  

According to mole concept:

6.022\times 10^{23} number of molecules occupy 1 mole of a gas.

As, 6.022\times 10^{23} number of hydrogen molecules has a mass of 2\times 10^{-3}kg

So, 1 molecule of hydrogen will have a mass of = \frac{2\times 10^{-3}kg}{6.022\times 10^{23}}\times 1=3.32\times 10^{-27}kg

  • To calculate the wavelength of a particle, we use the equation given by De-Broglie's wavelength, which is:

\lambda=\frac{h}{\sqrt{2mE_k}}

where,

\lambda = De-Broglie's wavelength = ?

h = Planck's constant = 6.624\times 10^{-34}Js

m = mass of 1 hydrogen molecule = 3.32\times 10^{-27}kg

E_k = kinetic energy of the particle = 6.21\times 10^{-22}J

Putting values in above equation, we get:

\lambda=\frac{6.624\times 10^{-34}Js}{\sqrt{2\times 3.32\times 10^{-27}kg\times 6.21\times 10^{-22}J}}

\lambda=3.26\times 10^{-10}m=3.26\AA    (Conversion factor: 1\AA=10^{-10}m )

Hence, the de-Broglie's wavelength of a hydrogen molecule is 3.26\AA

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Read 2 more answers
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