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Montano1993 [528]
3 years ago
15

ΔH for the reaction below is -826.0 kJ/mol. Calculate the heat change when a 69.03-g sample of iron is reacted.4Fe(s) + 3 O2(g)

--> Fe2O3(s)a. - 255.2 kJb. -510.5 kJc. -1020.9 kJd. -2042 kJe. -2.851 x 10^4 kJ
Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

Answer:

c. -1020.9 kJ

Explanation:

4Fe (s) + 3 O₂ (g) --> 2 Fe₂O₃(s)         ΔH  =  -826.0 kJ/mol.

atomic weight of iron = 56

69.03 g = 69.03 / 56

= 1.23268 moles

Heat released by 1.23268 moles

= 1.23268 x 826.0

= -1020.9 kJ .

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