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icang [17]
3 years ago
11

If there is sufficient water in the reaction system, how many grams of KOH can be produced from 22.2 g of K?

Chemistry
1 answer:
yulyashka [42]3 years ago
8 0

Answer: 31.9 g of KOH can be produced from 22.2 g of KOH

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} K=\frac{22.2g}{39g/mol}=0.57moles  

2K+2H_2O\rightarrow 2KOH+H_2  

According to stoichiometry :

2 moles of K produce = 2 moles of KOH

Thus 0.57 moles of K will produce=\frac{2}{2}\times 0.57=0.57moles  of KOH

Mass of KOH=moles\times {\text {Molar mass}}=0.57moles\times 56g/mol=31.9g

Thus 31.9 g of KOH can be produced from 22.2 g of KOH

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