A.LOW FREQUENCY, LOW ENERGY
Explanation:
Explanation:
To understand the properties of the wavelength of electromagnetic waves we first learn about the wavelength
Wavelength is the corresponding distance between the two adjacent waves, the wavelengths of electromagnetic spectrum range from longer than a football field to shorter than a diameter of an atom
The frequency is the number of waves that pass through a fixed point in a given amount of time. Frequencies of electromagnetic spectrum range from hundreds of waves per second to trillions of waves per second.
The energy level of the electromagnetic spectrum depends on their frequency level. Low-frequency level waves compared to high energy waves have less energy and are particularly harmless. High-frequency level waves have a definite amount of energy and are potentially very harmful.
By transmutation . this occurs through nuclear reactions in which an outside particle reacts with the nucleus and can be supplied by a particle accelerator . > off google (:
Answer:
10.56g
Explanation:
From the reaction equation, we can see that it is unbalanced. In the balanced state, 2 moles of KClO3 will yield 3 moles oxygen.
Let's calculate the actual number of moles now. We first divide the mass of the KClO3 by the molar mass. Molar mass of KClO3 = 39 + 35.5 + 3(16) = 122.5g/mol
The number of moles is thus 26.4/122.5 = 0.22 mole
If 2 moles KClO3 gave 3 moles O2, this means 0.22 moles will give (0.22 × 3)/2 = 0.33 mole
To calculate the mass of oxygen formed, we multiply the molecular mass of oxygen molecule by the number of moles
The molecular mass of oxygen molecule = 16 × 2 = 32g/mol
The mass formed = 32 × 0.33 = 10.56g
Like dissolves like
so water is polar
CCl4 is nonpolar
LiCl is polar
CH4 is nonpolar
PCl6 is nonpolar
so LiCl would dissolve
Answer:
8.2763 g
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:
pH=pKa+log[base]/[acid]
Where Ka is the dissociation constant of the acid.
Given that the acid dissociation constant = 3.5×10⁻⁸
pKa = - log (Ka) = - log (3.5×10⁻⁸) = 7.46
Given concentration of acid = [acid] = 0.244 M
pH = 6.733
So,
6.733 = 7.46+log[base]/0.244
[Base] = 0.0457 M
Given that Volume = 2 L
So, Moles = Molarity × Volume
Moles = 0.0457 × 2 = 0.0914 moles
Molar mass of potassium hypochlorite = 90.55 g/mol
Mass = Moles × Molar mass = (0.0914 × 90.55) g = <u>8.2763 g</u>
