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n = 1.5atm (15L) / .0821 (280k) = .98 mol NaCl
NaCl = 22.99g Na + 35.45g Cl = 58.44g NaCl
58.44g NaCl x .98 mol NaCl = 57.27g NaCl
Explanation:
hope you get it right :)
<span> 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
from the reaction 2 mol 4 mol
from the problem 5.4 mol 10.8 mol
M(CO2) = 12.0 +2*16.0 = 44.0 g/mol
10.8 mol CO2 * 44.0 g CO2/1 mol CO2 = 475.2 g CO2 </span>≈480 = 4.8 * 10² g
Answer is C. 4.8*10² g.
The complete question is: Match the following; Disulfide BondsA. Covalent interactions not found in all proteins.Peptide BondsB. Covalent interactions found in all proteins.Long-range interactionsC. Non-covalent interaction formed primarily on the interior of water-soluble proteins.Hydrophobic coreD. Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure.
The answer
Disulfide Bonds (Covalent interactions not found in all proteins.)
Peptide Bonds (Covalent interactions found in all proteins.)
Long-range interactions (Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure.)
Hydrophobic core. (Non-covalent interaction formed primarily on the interior of water-soluble proteins.)
Explanation:
The phrases have been given the right meaning enclosed in a parentheses. The should be matched accordingly as presented.
