This is not a function but the domain is x and the range is going to y so the first is the domain and the second box it the range
Answer
the answer is C
Step-by-step explanation:
nothing
Answer:
Step-by-step explanation:
There are no categorical antonyms for eleven. The numeral eleven is defined as: The cardinal number occurring after ten and before twelve.
Answer:
Derived from the Pythagorean Theorem, the distance formula is used to find the distance between two points in the plane. The Pythagorean Theorem,
a
2
+
b
2
=
c
2
, is based on a right triangle where a and b are the lengths of the legs adjacent to the right angle, and c is the length of the hypotenuse. The relationship of sides
|
x
2
−
x
1
|
and
|
y
2
−
y
1
|
to side d is the same as that of sides a and b to side c. We use the absolute value symbol to indicate that the length is a positive number because the absolute value of any number is positive. (For example,
|
−
3
|
=
3
. ) The symbols
|
x
2
−
x
1
|
and
|
y
2
−
y
1
|
indicate that the lengths of the sides of the triangle are positive. To find the length c, take the square root of both sides of the Pythagorean Theorem.
c
2
=
a
2
+
b
2
→
c
=
√
a
2
+
b
2
It follows that the distance formula is given as
d
2
=
(
x
2
−
x
1
)
2
+
(
y
2
−
y
1
)
2
→
d
=
√
(
x
2
−
x
1
)
2
+
(
y
2
−
y
1
)
2
We do not have to use the absolute value symbols in this definition because any number squared is positive.
A GENERAL NOTE: THE DISTANCE FORMULA
Given endpoints
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
, the distance between two points is given by
d
=
√
(
x
2
−
x
1
)
2
+
(
y
2
−
y
1
)
2
Step-by-step explanation:
Answer:
BRUH I DONT KNOW
Step-by-s
4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) DO ALL OF THAT TO FIND THE ANSWER
