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Slav-nsk [51]
3 years ago
15

Line a is parallel to line b, m<2 = 4x+44 , And m<6=6x+36. Find the value of x

Mathematics
1 answer:
Savatey [412]3 years ago
3 0

Answer:

x = 4

Step-by-step explanation:

<2 and <6 are equal because of the corresponding angles thm so:

4x + 44 = 6x + 36

4x - 6x = 36 - 44

-2x = -8

x = 4

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Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel
Nataliya [291]

Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e (x_o, y_o, z_o) and are parallel to \dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct

x = 4 + t

y = -5 + 2t

z = 2 + t

Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

\begin  {vmatrix} x = 4+ t   \\ \\  \dfrac{x-4}{1} = t  \begin {vmatirx} \end {vmatrix}\begin {vmatrix} y = - 5+2t  \\ \\ \dfrac{y+5}{2}  =t      \end {vmatrix}\begin {vmatrix} z =2+t  \\ \\ \dfrac{z-2}{1}  =t      \end {vmatrix}

∴

\dfrac{x-4}{1}= \dfrac{y+5}{2}=\dfrac{z-2}{1}

8 0
3 years ago
Could anyone find this?
lina2011 [118]

Answer:

Step-by-step explanation:

Since the squares have areas of 32u^2. The side lengths are

s=\sqrt{32}\\ \\ \text{By the Pythagorean Theorem}\\ \\ x^2=s^2+s^2\\ \\ x^2=32+32\\ \\ x^2=64\\ \\ x=\sqrt{64}\\ \\ x=8

8 0
3 years ago
How can 1% of 300 be used to determine 64% of 300? Enter your answers in the boxes to correctly complete the statement. 1% of 30
Ratling [72]

Answer:

1% of 300 is 3 so if you multiply that 3 by 64, you get 192 which is also 64% of 300

Step-by-step explanation:

.01 x 300 = 3

3 x 64 = 192

.64 x 300 = 192

4 0
2 years ago
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What is (57/tan30°)m^2
iVinArrow [24]
57\sqrt{3}m^2. Enjoy!
6 0
3 years ago
180kg, 250kg, 200kg, 209kg, 195kg, 205kg, 190kg, 188kg, 192kg. What is the IQR of the lion's weights.
velikii [3]

Answer:

18

Step-by-step explanation:

Given the data:

180kg, 250kg, 200kg, 209kg, 195kg, 205kg, 190kg, 188kg, 192kg

The interquartile range (IQR) = Q3 - Q1

Reordering the data:

180, 188, 190, 192, 195, 200, 205, 209, 250

Q3 = 3/4(n+1)th term

Q3 = 3/4(10) = 7.5 th term = (205+209)/2 = 207

Q1 = 1/4(n+1)th term

Q1 = 1/4(10) = 2.5th term = (188+190)/2 = 189

Q3 - Q1 = 207 - 189 = 18

3 0
3 years ago
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