To determine the force of the system, we use Newton's Second Law of motion which relates force and mass where they are directly proportional and the constant of proportionality is the acceleration. We calculate as follows:
F = ma
F = 10.41 kg ( 6.5 m/s^2 )
F = 67.67 kg m / s^2 or N
<h2>
Mass of object in Earth is 1.37 kg</h2>
Explanation:
On planet B where the magnitude of the free-fall acceleration is 1.91g , the object weighs 25.74 N.
We have
Weight = Mass x Acceleration due to gravity
On planet B
25.74 = Mass x 1.91 g
25.74 = Mass x 1.91 x 9.81
Mass = 1.37 kg
Mass is constant for an object. It will not change with location.
Mass of object in Earth = Mass of object in Planet B
Mass of object in Earth = 1.37 kg
Answer:
I=0.05 Amper
v=9 volts
Explanation:
I=V/R1
l=6/120=0.05Amper
voltage of 180ohm =IR2=0.05×180=9volts
Answer:
Its acceleration is 1.5
and the distance it has covered is 150 m.
Explanation:
Acceleration is a quantity that indicates the variation in speed of a moving body as time passes. That is, acceleration relates changes in velocity with the time in which they occur.
The average acceleration is defined as the relationship between the variation or change in the speed of a mobile and the time used in said change:

In this case:
- change in speed= final speed - initial speed= 15 m/s - 0 m/s= 15 m/s
- time= 10 s
Replacing:

and solving you get:
<u><em>acceleration= 1.5 </em></u>
<u><em></em></u>
Speed is a quantity that expresses the relationship between the space traveled by an object and the time used for it. This is:

So the distance can be calculated as:
distance= speed* time
In this case:
Replacing:
distance= 15 m/s* 10 s
and solving you get:
<u><em>distance= 150 m</em></u>
<u><em>Its acceleration is 1.5 </em></u>
<u><em> and the distance it has covered is 150 m.</em></u>
Answer:
<h2>
The potential difference increases </h2>
Explanation:
from the relation 
where E= electric field (force per coulomb)
V= voltage
d= distance
Hence the voltage is going to be V= E×d.
Therefore this means that increasing the distance increases the voltage.