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yawa3891 [41]
3 years ago
14

What is the relationship between force and motion described by Newton's first law

Physics
1 answer:
prisoha [69]3 years ago
4 0
Newtons First Law of Motion:
An object at rest stays at rest and an object in motion<span> stays in </span>motion <span>with the same speed and in the same direction unless acted upon by an unbalanced force.</span>

Therefore, the relationship between force and motion is that it takes force to change the speed or direction of any object in motion.
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A Force is applied onto a mass causing it to accelerate. If the same Force was applied to a SMALLER mass, what would happen to t
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In a crash test, a car with a mass of 1600 kg is initially moving at a speed of 20 m/s just before it collides with a barrier. T
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Answer:

The answer to the given points can be defined as follows:

Explanation:

In point 1:

\bold{v_f^2=  v_i^2+2as}\\\\\to v_f=0\\\\\to v_i=20 \frac{m}{s}\\\\\to s= 4.50\ m -3.60 \ m \\\\

      =0.9 \ m \\

put the value in the above formula:

\to 0=  20^2+2 \times a \times 0.9\\\\\to -1.8\ a=400\\\\\to -a= \frac{400}{1.8} \\\\ \to a= -222.22\ \  \frac{m}{s^2}

 \bold{v_f=v_i+at}\\\\\to 0=20+ (-222.22)t\\\\\to  222.22t=20\\\\\to t=\frac{20}{222.22}\\\\\to t= 0.0900 \ s\\\\\to v_{avg}=\frac{s}{t}=\frac{0.9}{t}= 10\ \frac{m}{s}

for point 2:

t= 0.0900 \ s  -\text{found above}

for point 3:

\to |a| = 222.22 \frac{m}{s^2} \text{found above}\\\\\to \bold{|F| = m \cdot |a|}\\\\

         =1600 \ kg \times 222.22 \ \frac{m}{s^2} \\\\= 3.55\times 10^{5} \ N

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