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Dvinal [7]
3 years ago
8

10 turns of wire are closely wound around a pencil as shown in the figure. when measured using a scale as shown, the length of t

otal turns is obtained 25mm. then a) What is the thickness of the wire? b) Express the thickness of the wire in centimetre.
please write correct answer
Physics
1 answer:
Mila [183]3 years ago
8 0

Answer:

a. The thickness of the wire is 2.5 mm.

b. The wire is 0.25 cm thick.

Explanation:

Number of turns of the wire = 10

The length of total turns = 25 mm

a. The thickness of the wire can be determined by;

thickness of the wire = \frac{length of total turns}{number of turns}

                           = \frac{25}{10}

                           = 2.5 mm

Therefore, the wire is 2.5 mm thick.

b. To determine the thickness of the wire in centimetre;

10 mm = 1 cm

So that,

2.5 mm = x

x  = \frac{2.5}{10}

   = 0.25 cm

The wire is 0.25 cm thick.

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The concave mirror is a spherical-shaped mirror that has an inner curved surface. Hence, option (4) is correct.

What is a concave mirror?

The concave mirrors are spherical-shaped mirrors that are painted on the outward surface. It is also known as the converging mirror, having the recessed inner reflecting surface.

  • The concave mirrors are generally used for the purpose to focus the light. For that, they might have a reflecting surface, curved inwards, and the reflection of light is limited to the single focal point.
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Thus, we can conclude that the surface of the concave mirror is curved inward. Hence, option (4) is correct.

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8 0
2 years ago
A 2.2 m -long wire carries a current of 7.2 A and is immersed within a uniform magnetic field B⃗ . When this wire lies along the
zimovet [89]

Answer:

Explanation:

Given that :

The current I =  7.2 A

The length vector L =   2.2 m i  

The force vector is = -2.6 j N

When L = 2.2 m i ; the

Force vector F = (2.6 i - 4.4 k) N

Compute the components of the magnetic field as follows:

F = I(L*B)

Replacing 7.2 A for I ; -2.6 j N for F & 2.2 m i for L

-2.6 j N = (7.2 A)(2.2 m i *(B_xi + B_yj+B_zk)

-2.6 j N = 15.84B_z \ and  \ 0 = 15.84B_y

B_z = -0.1641T  \ and \ B_y = 0

However in y direction ; we have :

(2.6 i - 4.4 k) = 7.2 A (2.2 mi*(B_xi+B_yj+B_zk)

- 2.6 = 15.84 B_z \ and \ -4.4 = 15.84 B_x

B_z = -0.1641 T \ and \ B_x = -0.2778T

Hence, the component of magnetic field is as follows:

B_x = -.02778T \ ; B_y = 0 T \  ; B_z =  - 0.1641 T)

5 0
3 years ago
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madreJ [45]

Answer:

L=4.19*10^{-6}H

Explanation:

The self-inductance of a solenoid is defined as:

L=\frac{\mu N^2A}{l}

Here \mu_0 is the the permeability of free space, N is the number of turns in the solenoid, A is the cross-sectional area os the solenoid and l its length. We replace the given values to get the self-inductance:

L=\frac{4\pi*10^{-7}\frac{T\cdot m}{A}(100)^2(1*10^{-4}m^2)}{30*10^{-2}m}\\L=4.19*10^{-6}H

4 0
4 years ago
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Leto [7]

Answer:

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Explanation:

7 0
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5 0
3 years ago
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