Answer:
(g-f) (-1)= sqrt(15)
(f/g)(-1)= 0
(g+f)(2)=sqrt(3)-3
(g*f)(2)=-3*sqrt(3)
Step-by-step explanation:
We have to eval the expressions given in the point indicated.
Lets start by the first equation
(g-f)(-1)= g(-1) - f(-1)= =
Now, lest continue with the others
(f/g)(-1)= f(-1)/g(-1)= (1-1)/sqrt(15)=0
(g+f)(2)=g(2)+f(2)=sqrt(3)-3
(g*f)(2)=g(2)*f(2)=sqrt(3)*(-3)=-3sqrt(3)
Answer:
6.82
Step-by-step explanation:
By congruence of triangles, the radius r of the cone base when its height is 1 meter satisfies the relation
r/1 = 2.5/6
(See picture attached)
So, r = 0.4166 meters when the water is 1 meter high.
The volume of a cone with radius of the base = R is given by
So, the volume of water when it is 1 meter high is
One minute later, the height of the water is 1 meter + 30 centimeters = 1.30 mt
The radius now satisfies
r/1.3 = 2.5/6
and now the radius of the base is
r = 0.5416 mt
and the new volume of water is
So, the water is raising at a speed of
0.3071-0.1871 = 0.12
This speed equals the difference between the water being pumped and the water leaking,
So,
<em>0.12 = Speed of water being pumped -6.8 </em>
and
Speed of water being pumped = 6.8+0.12 = 6.82
