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frosja888 [35]
3 years ago
12

Select the quadratic function that corresponds to each graph below

Mathematics
2 answers:
Shtirlitz [24]3 years ago
7 0

Answer:

1.  y=(x+3)^2-4

2. y=(x+4)^2-3

3. y=(x-3)^2+4

4. y=(x-4)^2+3

Step-by-step explanation:

The vertex from of a quadratic function is

y=a(x-h)^2+k

where, a is constant and (h,k) is vertex.

(1)

The vertex of the parabola is (-3,-4).

y=a(x-(-3))^2+(-4)

y=a(x+3)^2-4

The graph is passes through the point (-1,0).

0=a(-1+3)^2-4

4=4a

1=a

y=(1)(x+3)^2-4

y=(x+3)^2-4

Therefore, the required equation is y=(x+3)^2-4.

Similarly,

(2)

The vertex of the parabola is (-4,-3).

y=a(x+4)^2-3

The graph is passes through the point (-3,-2).

-2=a(-3+4)^2-3

a=1

Therefore, the required equation is y=(x+4)^2-3.

(3)

The vertex of the parabola is (3,4).

y=a(x-3)^2+4

The graph is passes through the point (2,5).

5=a(2-3)^2+4

a=1

Therefore, the required equation is y=(x-3)^2+4.

(4)

The vertex of the parabola is (4,3).

y=a(x-4)^2+3

The graph is passes through the point (3,4).

4=a(3-4)^2+3

a=1

Therefore, the required equation is y=(x-4)^2+3.

ozzi3 years ago
5 0
C B A are the orders of the answers
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Step-by-step explanation:

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4 years ago
Records indicate that x years after 2008, the average property tax on a three bedroom home in a certain community was T(x) =20x^
dem82 [27]

Answer:

a) 40 dollars

b) 480 dollars

Step-by-step explanation:

Given the average property tax on a three bedroom home in a certain community modelled by the equation T(x) =20x²+40x+600, the rate at which the property tax is increasing with respect to time in 2008 can be derived by solving for the function T'(x) at x=0

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Hence the property tax was increasing at a rate of 40dollars with respect to the initial year (2008).

b) There are 4 years between 2008 and 2012. To know how much that the tax change between the years 2008 and 2012, we will find T(4) - T(0)

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4 years ago
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3 years ago
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