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lesya [120]
3 years ago
12

A car accelerates from 0 to 72 km/ hour in 8 sec. what is the cars acceleration?

Physics
1 answer:
timofeeve [1]3 years ago
5 0

Explanation:

Initial Velocity (u) = o m/s

Final Velocity (V) =(72*1000)/1*60*60 m/s

= 20m/s

time (t) =8 sec

Acceleration(a)= v-u /t

=(20-0)/8

=2.5 m/s^2

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3 years ago
A guitar string is 90 cm long and has a mass of 3.7 g . The distance from the bridge to the support post is L=62cm, and the stri
zvonat [6]

To solve this problem we will apply the concept of frequency in a string from the nodes, the tension, the linear density and the length of the string, that is,

f = \frac{n}{2L}(\sqrt{\frac{T}{\mu}})

Here

n = Number of node

T = Tension

\mu = Linear density

L = Length

Replacing the values in the frequency and value of n is one for fundamental overtone

f = \frac{n}{2L}(\sqrt{\frac{T}{\mu}})

f = \frac{1}{2(62*10^{-2})}(\sqrt{\frac{500}{(\frac{3.7*10^{-3}}{90*10^{-2}})}})

\mathbf{f = 281.2Hz}

Similarly plug in 2 for n for first overtone and determine the value of frequency

f = \frac{n}{2L}(\sqrt{\frac{T}{\mu}})

f = \frac{2}{2(62*10^{-2})}(\sqrt{\frac{500}{(\frac{3.7*10^{-3}}{90*10^{-2}})}})

\mathbf{f = 562.4Hz}

Similarly plug in 3 for n for first overtone and determine the value of frequency

f = \frac{n}{2L}(\sqrt{\frac{T}{\mu}})

f = \frac{3}{2(62*10^{-2})}\bigg (\sqrt{\frac{500}{(\frac{3.7*10^{-3}}{90*10^{-2}})}} \bigg)

\mathbf{f= 843.7Hz}

4 0
3 years ago
How are force and motion related
sp2606 [1]
Force is used to put things in motion you can’t have motion without force!
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5 0
2 years ago
If the speed of an object is increasing, then the forces acting on that object must be ________.
In-s [12.5K]

Answer:

Unbalanced.

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5 0
3 years ago
A 2.00-kilogram object weighs 19.6 newtons on earth. if the acceleration due to gravity on mars is 3.71 meters per second2, what
Harrizon [31]
Recall that mass is the amount of matter present in a body. That means it's a property that is consistent regardless of the body's current location, gravity's pull on the body, etc. 

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Answers: 2.00 kilograms
4 0
3 years ago
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